Thank you for your response. I apologize for cross posting. I will try the
way you suggested. Thanks again.
On Mon, Nov 10, 2014 at 11:08 AM, Michael Dewey
wrote:
>
>
> On 10/11/2014 14:20, huang jialin wrote:
>
>> Hi,
>>
>> I am planning to use BHHR method to conduct a meta-analysis, including
On 10/11/2014 14:20, huang jialin wrote:
Hi,
I am planning to use BHHR method to conduct a meta-analysis, including
calculation of a summary effect size and subgroup analysis. Meanwhile, I
need to draw a trim-and-fill plot of all the effect sizes. However, MAd
package cannot achieve the goal,
Hi,
I am planning to use BHHR method to conduct a meta-analysis, including
calculation of a summary effect size and subgroup analysis. Meanwhile, I
need to draw a trim-and-fill plot of all the effect sizes. However, MAd
package cannot achieve the goal, while meta and metafor do. But it seems
meta
On 9/18/07, Nair, Murlidharan T <[EMAIL PROTECTED]> wrote:
>
>
> -Original Message-
> From: Deepayan Sarkar [mailto:[EMAIL PROTECTED]
> Sent: Monday, September 17, 2007 5:10 PM
> To: Nair, Murlidharan T
> Cc: [EMAIL PROTECTED]
> Subject: Re: [R] MAD
>
EMAIL PROTECTED]
> Sent: Monday, September 17, 2007 5:10 PM
> To: Nair, Murlidharan T
> Cc: [EMAIL PROTECTED]
> Subject: Re: [R] MAD
>
> On 9/17/07, Nair, Murlidharan T <[EMAIL PROTECTED]> wrote:
>> I am calculating the median absolute deviation using mad function, and
-Original Message-
From: Deepayan Sarkar [mailto:[EMAIL PROTECTED]
Sent: Monday, September 17, 2007 5:10 PM
To: Nair, Murlidharan T
Cc: [EMAIL PROTECTED]
Subject: Re: [R] MAD
On 9/17/07, Nair, Murlidharan T <[EMAIL PROTECTED]> wrote:
>
> I am calculating the median absolu
I am calculating the median absolute deviation using mad function, and
it tends to ignore the parameter constant=1, when I am calculating it
for x=seq(1:5). Am I missing something here?
x<-seq(1:5)
mad(x)# gives [1] 1.4826
mad(x, constant=1)# gives [1] 1
#Here is the long form
dev.from.median<-ab
On 9/17/07, Nair, Murlidharan T <[EMAIL PROTECTED]> wrote:
>
> I am calculating the median absolute deviation using mad function, and
> it tends to ignore the parameter constant=1, when I am calculating it
> for x=seq(1:5). Am I missing something here?
>
> x<-seq(1:5)
> mad(x)# gives [1] 1.4826
> m
8 matches
Mail list logo