Re: [R] Looping help

2015-07-31 Thread Jim Lemon
at[row,qval] to the return values } } Jim > From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of April > Smith > Sent: Friday, July 31, 2015 2:21 AM > To: r-help@r-project.org > Subject: [R] Looping help > > I have never looped before and know I need to. I am unsure

Re: [R] Looping help

2015-07-30 Thread PIKAL Petr
[mailto:r-help-boun...@r-project.org] On Behalf Of April > Smith > Sent: Friday, July 31, 2015 2:21 AM > To: r-help@r-project.org > Subject: [R] Looping help > > I have never looped before and know I need to. I am unsure how to > proceed: > > >- Action I need do

[R] Looping help

2015-07-30 Thread April Smith
I have never looped before and know I need to. I am unsure how to proceed: - Action I need done: d(Data[1,2:399], q=0, boot=TRUE, boot.arg=list(num.iter=1000)) - I need this to happen to all rows, I need All[1,2:399] to increase to All[2:399], etc. - But I also need the results fr

Re: [R] R looping help

2013-05-17 Thread Adams, Jean
replacement length > 13: In rsquares[st] <- ssr/(var(yi) * (length(xi) - 1)) : > number of items to replace is not a multiple of replacement length > 14: In pValues[st] <- 1 - pf(fRatio, 1, length(xi) - 2) : > etc etc > > Sorry if I haven't set this post out right, o

Re: [R] R looping help

2013-05-16 Thread rishard
abble.com/R-looping-help-tp4667180p4667260.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-gui

Re: [R] R looping help

2013-05-16 Thread MacQueen, Don
ngth(xi) - 2) : > number of items to replace is not a multiple of replacement length >13: In rsquares[st] <- ssr/(var(yi) * (length(xi) - 1)) : > number of items to replace is not a multiple of replacement length >14: In pValues[st] <- 1 - pf(fRatio, 1, length(xi) - 2) : >etc

[R] R looping help

2013-05-16 Thread rishard
(xi) - 1)) : number of items to replace is not a multiple of replacement length 14: In pValues[st] <- 1 - pf(fRatio, 1, length(xi) - 2) : etc etc Sorry if I haven't set this post out right, or haven't provided enough information. But can anyone see why it is not giving me any returns fo