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>
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> Cheers
>
> Petr
>
>
>
>
>
> *From:* dusa.adr...@gmail.com [mailto:dusa.adr...@gmail.com] *On Behalf
> Of *Adrian Du?a
> *Sent:* Monday, October 10, 2016 12:26 PM
> *To:* Christoph Puschmann
> *Cc:* r-help@r-project.org; PIKAL Petr
&g
il.com [mailto:dusa.adr...@gmail.com] On Behalf Of Adrian
Du?a
Sent: Monday, October 10, 2016 12:26 PM
To: Christoph Puschmann
Cc: r-help@r-project.org; PIKAL Petr
Subject: Re: [R] Loop to check for large dataset
This is an example of how a reproducible code looks like, assuming you have
three columns i
This is an example of how a reproducible code looks like, assuming you have
three columns in your dataset named S (store), P (product) and W (week),
and also assuming they have integer values from 1 to 19, 1 to 22 and 1 to
157 respectively:
#
mydata <- expand.grid(seq(19), seq(22), seq(15
ull set STORE, WEEK and description and merge it
with original data by merge.
Cheers
Petr
From: Christoph Puschmann [mailto:c.puschm...@student.unsw.edu.au]
Sent: Monday, October 10, 2016 9:34 AM
To: PIKAL Petr ; r-help@r-project.org
Subject: Re: [R] Loop to check for large dataset
Dear Petr,
Dear Petr,
I attached a sample file, which contains the first 4 products.
It is more that I have: 157 weeks, 19 different Stores and 22 products:
157*19*22 = 65,626 rows. And as I sated I have roughly 63,127 rows. (so some
have to be missing).
All the best,
Christoph
Hi
see in line
> -Original Message-
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Christoph
> Puschmann
> Sent: Sunday, October 9, 2016 1:27 AM
> To: Adrian Dușa
> Cc: r-help@r-project.org; Christoph Puschmann
>
> Subject: Re: [R] Loop to
Dear Adrian,
Yes it is a cyclical data set and theoretically it should repeat this interval
until 61327. The data set itself is divided into 2 Parts:
1. Product category (column 10)
2. Number of Stores Participating (column 01)
Overall there are 22 different products and in each you have 19 diffe
It would help to have a minimal, reproducible example.
Unless revealing the structure of your FD object, it is difficult to
understand how a column having 61327 values would be "consistent over an 1
to 157 interval": is this interval cyclic until it reaches 61327 values?
>From your example using F
Hello,
I'm not at all sure if the following is what you need but instead of
for (i in length(FD$WEEK))
try
for (i in 1:length(FD$WEEK))
or even better
for (i in seq_len(FD$WEEK))
And use Control[i, 1], not Control[, 1]
Hope thi helps,
Rui Barradas
Citando Christoph Puschmann :
Hey
Hey all,
I would like to know if anyone, can put in the right direction of the following
problem:
I am currently want to use it to check if a column with a length of 61327 is
consistent over an 1 to 157 interval until the end of the column. In the case
the interval is interrupted I want to kno
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