& -> AND -> results only TRUE if both inputs are TRUE. Hence: FALSE AND
unknown = FALSE, TRUE AND unknown = unknown
| -> OR -> results in TRUE as soon as one of the inputs is TRUE. Hence FASE
or unknown = unknown, TRUE or unknown = TRUE
TRUE == NA and FALSE == NA compares TRUE/FALSE against unknown
Hi,
I need to understand the inconsistent behaviour of & and I operators when
used with NA.
The code below explains this inconsistency
> TRUE & NA
[1] NA
> FALSE & NA
[1] FALSE
> TRUE & NA
[1] NA
> FALSE | NA
[1] NA
> TRUE | NA
[1] TRUE
> TRUE == NA
[1] NA
> FALSE == NA
[1] NA
[[a
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