Imagine a list of two arrays. The first array is like a vector that
contains ten 2x2 matrices. The second array contains two vectors of 2x2
matrices of length five and three, respectively. I run the code and it
gives me what I want for the first array. However, it disappoints me for
the second arra
x = c( 4 , 4 , 0 )
y = c( 1 , 0 , 2 )
t = c( 1 , 2, 2 )
r <- as.vector(table(t))
Nx <- vector("list",length(unique(t)))
Ny <- vector("list",length(unique(t)))
n <- vector("list",length(unique(t)))
for(i in 1:length(unique(t))){
Nx[[i]] <- array(0,dim=c(1,r[i],1))+x[t==i]+1
Ny[[i]]
This time the code works, except for the spurious "}" at the end.
I still don't know what the goal is.
Please help yourself and us by putting spaces around assignment arrows
a <- b
instead of the hard-to-read
a<-b
and putting spaces after ","
## Let
a <- 12
## Does
a<-3
## mean
a <- 3
## or
a< -
I am "refreshing" the code for the problem
x = c( 4 , 4 , 0 )
y = c( 1 , 0 , 2 )
t = c( 1 , 2, 2 )
r<-as.vector(table(t))
Nx<-vector("list",length(unique(t)))
Ny<-vector("list",length(unique(t)))
n<-vector("list",length(unique(t)))
for(i in 1:length(unique(t))){
Nx[[i]]<-array(0,d
Your example is hard to understand because it includes multiple copies of
the
number "1". Let me do something with different values and see if it gets
what
you are after. Your code as posted can't work because the variable n is not
defined.
result <- list(a=array(1:48, dim=c(2,2,3,4)),
Dear all,
I want to obtain the following result
[[1]]
, , 1, 1
[,1] [,2]
[1,]11
[2,]11
, , 2, 1
[,1] [,2]
[1,]11
[2,]11
, , 9, 1
[,1] [,2]
[1,]11
[2,]11
, , 10, 1
[,1] [,2]
[1,]11
[2,]11
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