Hi David,
Try
> x[[2]][1]
[1] 4
>
A.K.
- Original Message -
From: David Perlman
To: r-help@r-project.org
Cc:
Sent: Monday, May 21, 2012 8:07 PM
Subject: [R] List indexing question
Consider the following:
> x<-list(c(1,2,3),c(4,5,6))
> x[1]
[[1]]
[1] 1 2 3
> x[
There is also the recursive extraction with "[[":
x[[c(2, 1)]]
[1] 4
>From ?Extract
" ‘[[’ can be applied recursively to lists, so that if the single
index ‘i’ is a vector of length ‘p’, ‘alist[[i]]’ is equivalent to
‘alist[[i1]]...[[ip]]’ providing all but the final indexing
resu
It's a little funny, you actually need
x[[2]][1]
What's going on is the following:
lists can contain anything else in R, including more lists so
subsetting them takes a hair more work. x[2] returns the sublist of x
containing the second list element -- this is, however, not the same
as x[[2]] wh
Consider the following:
> x<-list(c(1,2,3),c(4,5,6))
> x[1]
[[1]]
[1] 1 2 3
> x[2]
[[1]]
[1] 4 5 6
So far that all seems reasonable. But now there's a problem. I'm used to
python, where I would say x[2][1] and get the value 4. But I can't figure out
how to do that in R.
> x[2][1]
[[1]]
[1]
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