D" "F" "G" "H" "J" "K" "L" "M" "N" "O" "P" "Q"
> "R" "S" "T" "V" "X"
> # [20] "Y" "Z"
>
> There are times wh
; "P" "Q"
"R" "S" "T" "V" "X"
# [20] "Y" "Z"
There are times when you want to know if certain factor levels
do not appear in a subset of the original data.
-
David L Carls
On Jul 24, 2013, at 11:35 AM, David Winsemius wrote:
>
> On Jul 24, 2013, at 6:25 AM, Borja Rivier wrote:
>
>> Hi all,
>>
>> I am having a bit of trouble using the levels() function.
>> I have a factor with many elements, and when I use the function levels() to
>> extract the list of unique el
On Jul 24, 2013, at 6:25 AM, Borja Rivier wrote:
> Hi all,
>
> I am having a bit of trouble using the levels() function.
> I have a factor with many elements, and when I use the function levels() to
> extract the list of unique elements, some of the elements returned are not
> actually in the fa
Hi,
vec1<- factor(1:5,levels=1:10)
vec1
#[1] 1 2 3 4 5
#Levels: 1 2 3 4 5 6 7 8 9 10
vec2<-droplevels(vec1)
levels(vec2)
#[1] "1" "2" "3" "4" "5"
vec2
#[1] 1 2 3 4 5
#Levels: 1 2 3 4 5
A.K.
Hi all,
I am having a bit of trouble using the levels() function.
I have a factor with many element
Hi all,
I am having a bit of trouble using the levels() function.
I have a factor with many elements, and when I use the function levels() to
extract the list of unique elements, some of the elements returned are not
actually in the factor.
For example I would have this:
> vector <- dataset$Benc
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