Thank you Kevin. I'm looking forward to trying your function when I get back
to the office.
Jerry Floren
Minnesota Department of Agriculture
Kevin Wright-5 wrote:
>
> Here is a simple function I use. It uses Median +/- 5.2 * MAD. If I
> recall, this flags about 1/2000 of values from a true
Here is a simple function I use. It uses Median +/- 5.2 * MAD. If I
recall, this flags about 1/2000 of values from a true Normal distribution.
is.outlier = function (x) {
# See: Davies, P.L. and Gather, U. (1993).
# "The identification of multiple outliers" (with discussion)
# J. Ame
"straightforward" scientific data. It is a conundrum I cannot resolve,
> but
> that does not mean I can deny it.
>
> Finally, a word of wisdom from a long-ago engineering colleague:
> "Whenever I
> see an outlier, I'm never sure whether to throw it away or pa
--Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On
Behalf Of Jerry Floren
Sent: Wednesday, December 30, 2009 9:47 AM
To: r-help@r-project.org
Subject: Re: [R] Identifying outliers in non-normally distributed data
Greetings:
I could also use guidanc
Cheers,
Bert Gunter
Genentech Nonclinical Statistics
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Jerry Floren
Sent: Wednesday, December 30, 2009 9:47 AM
To: r-help@r-project.org
Subject: Re: [R] Identifying outliers i
Greetings:
I could also use guidance on this topic. I provide manure sample proficiency
sets to agricultural labs in the United States and Canada. There are about
65 labs in the program.
My data sets are much smaller and typically non-symmetrical with obvious
outliers. Usually, there are 30 to 6
John wrote:
Hello,
I've been searching for a method for identify outliers for quite some
time now. The complication is that I cannot assume that my data is
normally distributed nor symmetrical (i.e. some distributions might
have one longer tail) so I have not been able to find any good tests.
Th
Hello,
I've been searching for a method for identify outliers for quite some
time now. The complication is that I cannot assume that my data is
normally distributed nor symmetrical (i.e. some distributions might
have one longer tail) so I have not been able to find any good tests.
The Walsh's Test
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