On Wed, 5 Oct 2011, Petr PIKAL wrote:
But you do not loose them, your data frame is cut according to sites
variable and put into a list
I know this, Petr. But adding them to the database table ensures that the
information is there, too.
This brings up another question, but I should put th
Hi
>
> On Wed, 5 Oct 2011, Petr PIKAL wrote:
>
> > Hm. I seldom use such approach. In your original request you said you
want
> > split your data to smaller data frames based on sites
>
> Petr,
>
>I need the additional information in the database, too.
But you do not loose them, your dat
On Wed, 5 Oct 2011, Rich Shepard wrote:
First thing this morning I'm upgrading to 2.13.2 and hoping that this
fixes an issue that just showed up yesterday afternoon: not being able to
access function help pages. For example, I tried ?subset and ?split because
I thought the latter is really what
On Wed, 5 Oct 2011, Petr PIKAL wrote:
Hm. I seldom use such approach. In your original request you said you want
split your data to smaller data frames based on sites
Petr,
I need the additional information in the database, too.
From what we know it is difficult to say if there is some co
>
> On Tue, 4 Oct 2011, Sarah Goslee wrote:
>
> > You asked for pointers, and didn't provide a reproducible example, so
I
> > offered a pointer.
>
> Sarah,
>
>I did not realize that your pointer was to the factor component of
the
> subset() command.
>
>I think the most parsimonious t
On Tue, 4 Oct 2011, R. Michael Weylandt wrote:
No, that was just a typo on my end:
the correct order of arguments should have been
ff <- grepl("BC-", ff)
Michael,
Thank you.
Rich
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On Tue, 4 Oct 2011, Sarah Goslee wrote:
You asked for pointers, and didn't provide a reproducible example, so I
offered a pointer.
Sarah,
I did not realize that your pointer was to the factor component of the
subset() command.
I think the most parsimonious thing for me to do is to modify
No, that was just a typo on my end:
the correct order of arguments should have been
ff <- grepl("BC-", ff)
On Tue, Oct 4, 2011 at 3:07 PM, Rich Shepard wrote:
> On Tue, 4 Oct 2011, R. Michael Weylandt wrote:
>
>> This isn't going to be the most elegant, but it should work:
>> ## Get the factors
... and, as an aside, if you had simply searched within R for (the
obvious?!)
??wildcard
you would have received the suggestion for glob2rx() in utils, which
actually would have enabled you to use a familiar wildcard expression.
However, the answers you've already received are simpler and more
st
?grep
?names
Use indexing by name [, namevector]
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On Tue, 4 Oct 2011, R. Michael Weylandt wrote:
This isn't going to be the most elegant, but it should work:
## Get the factors as characters
ff <- as.character(chemdata$site)
## Identify those that match what you want
ff <- grepl(ff, "BC-")
Michael,
Apparently grep works differently in R
Hi Rich,
On Tue, Oct 4, 2011 at 2:58 PM, Rich Shepard wrote:
> On Tue, 4 Oct 2011, Sarah Goslee wrote:
>
>> You can use something like this:
>>
>>> testdata <- c("A1", "A2", "A3", "B1", "B2", "B3")
>>> grep("^A", testdata)
>>
>> [1] 1 2 3
>>>
>>> grepl("^A", testdata)
>>
>> [1] TRUE TRUE TRUE
On Tue, 4 Oct 2011, Sarah Goslee wrote:
You can use something like this:
testdata <- c("A1", "A2", "A3", "B1", "B2", "B3")
grep("^A", testdata)
[1] 1 2 3
grepl("^A", testdata)
[1] TRUE TRUE TRUE FALSE FALSE FALSE
Sarah,
I don't see how this gives me a data frame containing only thos
This isn't going to be the most elegant, but it should work:
## Get the factors as characters
ff <- as.character(chemdata$site)
## Identify those that match what you want
ff <- grepl(ff, "BC-")
now use this logical vector to subset
chemdata[ff, ]
Can't test, but should be good to go assuming
Hi Rich,
You can use something like this:
> testdata <- c("A1", "A2", "A3", "B1", "B2", "B3")
> grep("^A", testdata)
[1] 1 2 3
> grepl("^A", testdata)
[1] TRUE TRUE TRUE FALSE FALSE FALSE
Sarah
On Tue, Oct 4, 2011 at 2:39 PM, Rich Shepard wrote:
> I have a data frame called chemdata with t
I have a data frame called chemdata with this structure:
str(chemdata)
'data.frame': 14886 obs. of 4 variables:
$ site: Factor w/ 148 levels "BC-0.5","BC-1",..: 104 145 126 115 114 128
124 2 3 3 ...
$ sampdate: Date, format: "1996-12-27" "1996-08-22" ...
$ param : Factor w/ 8 lev
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