"ID_Date", "Run1", "Run2",
>> > "Run3", "Run4", "Run5"), row.names = c(NA, 4L), class = "data.frame")
>> > require(stringr)
>> > report <- t(apply(report, 1, function(x) {str_replace(x, "\\?&quo
(34 ?
66)"
$ Run4 : chr "0 ( ? )" "n (0 ? 0)" "0 ( ? )" "0 ( ? )"
$ Run5 : chr "0 ( ? )" "n (0 ? 0)" "0 ( ? )" "0 ( ? )"
names(report)[1] # I can extract the column name here
[1] "Date"
But after
? )&0 ( ?
> )\tabularnewline
> 2&3/13/2010&n (0 ? 0)&n (0 ? 0)&n (0 ? 0)&n (0 ? 0)&n (0 ? 0)\tabularnewline
> 3&3/14/2010&893 (110 ? 146)&337 (67 ? 74)&10,602 (32 ? 52)&0 ( ? )&0 ( ?
> )\tabularnewline
> 4&3/15/2010&140 (111
xpr{report[1,1]} &
> > &\Sexpr{report[1,2]} and so on, but I can't access my column headers
> > with \Sexpr{} because I can't find the way to reference run1,run2,run3 and
>run4.
> > Sorry if I am not explain myself really well.
>
> Wouldn't this j
or perhaps you want specific items in that
vector?
Sexpr{names(report)[1]}, Sexpr{names(report)[2]}, etc
--
David.
- Original Message
From: Duncan Murdoch
To: Felipe Carrillo
Cc: r-h...@stat.math.ethz.ch
Sent: Mon, July 12, 2010 2:18:15 PM
Subject: Re: [R] How to select the
z.ch
> Sent: Mon, July 12, 2010 2:18:15 PM
> Subject: Re: [R] How to select the column header with \Sexpr{}
>
> On 12/07/2010 5:10 PM, Felipe Carrillo wrote:
> > Hi:
> > Since I work with a few different fish runs my column headers change
>everytime
> > I start a new
On 12/07/2010 5:10 PM, Felipe Carrillo wrote:
Hi:
Since I work with a few different fish runs my column headers change everytime
I start a new Year. I have been using \Sexpr{} for my row and columns and now
I am trying to use with my report column headers. \Sexpr{1,1} is row 1 column 1,
what can
Hi:
Since I work with a few different fish runs my column headers change everytime
I start a new Year. I have been using \Sexpr{} for my row and columns and now
I am trying to use with my report column headers. \Sexpr{1,1} is row 1 column 1,
what can I use for headers? I tried \Sexpr{0,1} but swea
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