Thanks, this works, replacing the NA values with the "000/000' string.
On 4/05/2010 11:20 PM, Muhammad Rahiz wrote:
Hi Nevil,
You can try a method like this
x <- c(rnorm(5),rep(NA,3),rnorm(5)) # sample data
dat <- data.frame(x,x) # make sample dataframe
dat2 <- as.matrix(
try x[is.na(x)] <- "000/000"
Bart
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?replace
Something like this should work
replace(df1, is.na(df1), "000/000")
--- On Tue, 5/4/10, Nevil Amos wrote:
> From: Nevil Amos
> Subject: [R] How to replace all values in a data.frame with another (
> not 0) value
> To: r-h...@stat.math.ethz.ch
> Received
Hi Nevil,
You can try a method like this
x <- c(rnorm(5),rep(NA,3),rnorm(5)) # sample data
dat <- data.frame(x,x) # make sample dataframe
dat2 <- as.matrix(dat) # conver to matrix
y <- which(is.na(dat)==TRUE) # get index of NA values
dat2[y] <- "
000/000 returns NaN, which is no different than NA unless you want it as
string i.e. "000/000"
Muhammad
Lanna Jin wrote:
Try: "x[which(is.na(x)),] <- 000/000", where is x is your data frame
-
Lanna Jin
lanna...@gmail.com
510-898-8525
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Whoops, my bad. Maybe try using "gsub"
-
Lanna Jin
lanna...@gmail.com
510-898-8525
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Sent from the R help mailing list archive at Nabbl
Try: "x[which(is.na(x)),] <- 000/000", where is x is your data frame
-
Lanna Jin
lanna...@gmail.com
510-898-8525
--
View this message in context:
http://r.789695.n4.nabble.com/How-to-replace-all-NA-values-in-a-data-frame-with-another-not-0-value-tp2125458p2125464.html
Sent from the R help
I need to replace occurrences in multiple columns in a data.frame
with "000/000"
how do I achieve this?
Thanks
Nevil Amos
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