On 04-Sep-10 19:27:54, Yi wrote:
> Enh, I see.
> It totally makes sense.
> Thank you for your perfect explanation.
> Enjoy the long weekend~
> Yi
You're welcome! Earlier I tried an experiment with rejection
sampling, which seems to work well for the case where you want
mean of the sampled values t
There is still ambiguity (and I think some misunderstanding)
in your query! First, Barry's code does yield integers as the
values in the sample. As a smaller illustrative example:
x <- sample(17:23,20,TRUE)
will give results like
x
# [1] 21 17 23 21 17 17 19 18 17 17 17 22 20 23 20 20 18 2
On Sat, Sep 4, 2010 at 8:07 AM, Yi wrote:
> Sorry I forgot to talk about the range.
>
> But as an example, range (17,23) works.
>
> In your codes, mean is not exactly 20 and the samples are not integer.
The samples *are* integers. sample(17:23,1,TRUE) returns integers.
> However, what I wan
Sorry I forgot to talk about the range.
But as an example, range (17,23) works.
In your codes, mean is not exactly 20 and the samples are not integer.
However, what I want is integers with mean 20 exactly.
Any tips?
Thanks
On Thu, Sep 2, 2010 at 12:16 AM, Barry Rowlingson <
b.rowling...@lancas
On Thu, Sep 2, 2010 at 7:17 AM, Yi wrote:
> Hi, folks,
>
> runif (n,min,max) is the typical code for generate R.V from uniform dist.
>
> But what if we need to fix the mean as 20, and we want the values to be
> integers only?
It's not clear what you want. Uniformly random integers with expected
Hi, folks,
runif (n,min,max) is the typical code for generate R.V from uniform dist.
But what if we need to fix the mean as 20, and we want the values to be
integers only?
Thanks
[[alternative HTML version deleted]]
__
R-help@r-project.org ma
6 matches
Mail list logo
