Here is the solution
data<-read.table("d:/ftse.txt",header=TRUE)
wDay<-as.Date(data$date,"%d/%m/%Y")
data<-data.frame(data[,-1])
price<-data$ftse100
data<-data.frame(price,wDay)
data[1:10,]
a<-as.Date("03/01/1989","%d/%m/%Y")
b<-as.Date("31/01/2007","%d/%m/%Y")
ab<-seq(a,b,by=1)
c<-
Hello,
altough I'm not an expert, I found a solution (maybe not the most
elegant.)
d<-as.Date(c("2000/01/03","2000/01/05","2000/01/19","2000/01/28"))
r<-rnorm(4)
da<-data.frame(d,r)
a<-as.Date("01/01/2000","%d/%m/%Y")
b<-as.Date("30/01/2000","%d/%m/%Y")
ab<-seq(a,b,by=1)
c<-format(ab,
The last line should have been:
z <- merge(r = tmp.z, weekday = as.numeric(format(time(date.z), "%w")),
h = !tmp.z)
On Fri, Apr 4, 2008 at 8:25 AM, Gabor Grothendieck
<[EMAIL PROTECTED]> wrote:
> Have a look at the zoo package. After reading
> in the data its only 2 lines of code.
>
> Not
If I understand:
res <- merge(date, da, by.x = "ab", by.y="d", all=T)
res$h <- 0
res$h[is.na(res$r)] <- 1
res$r[is.na(res$r)] <- 0
On Fri, Apr 4, 2008 at 8:49 AM, saikat sarkar <[EMAIL PROTECTED]> wrote:
>
> Hi,
>
> R experts. I am a new user of R and trying to learn this program.
>
> I have a
Have a look at the zoo package. After reading
in the data its only 2 lines of code.
Note that zoo objects can be numeric or
factor but not both so we have represented
the day of the week as 1 for Mon, etc.
in the final object. You could convert it
to a data frame at the end if you really
need t
Hi,
R experts. I am a new user of R and trying to learn this program.
I have a problem. Here is the code.
d<-as.Date(c("2000/01/03","2000/01/05","2000/01/19","2000/01/28"))
r<-rnorm(4)
da<-data.frame(d,r)
a<-as.Date("01/01/2000","%d/%m/%Y")
b<-as.Date("30/01/2000","%d/%m/%Y")
ab<-seq(a,b,by=
Hi,
R experts. I am a new user of R and trying to learn this program.
I have a problem. Here is the code.
d<-as.Date(c("2000/01/03","2000/01/05","2000/01/19","2000/01/28"))
r<-rnorm(4)
da<-data.frame(d,r)
a<-as.Date("01/01/2000","%d/%m/%Y")
b<-as.Date("30/01/2000","%d/%m/%Y")
ab<-seq(a,b,by=
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