Re: [R] Help with prob in sample()

Oops, my answer was for when replace=TRUE, when replace=FALSE it uses a different method, but that method is described on the help page for sample. Essentially it chooses the first number, then removes that value from x and prob, then chooses the next (rescaling prob again), etc. On Fri, Mar 7, 2

Re: [R] Help with prob in sample()

Essentially what the sample function is doing (though it does it in a much more efficient way I expect) is the equivalent of this code: i <- c(1:10) myProbs <- c(0.1, 0.1, 0.1, 0.1, 0.1, 0.9, 0.9, 0.9, 0.9, 0.9) myProbs <- myProbs/sum(myProbs) cp <- c(0,cumsum(myProbs)) i[findInterval( runif(5),

[R] Help with prob in sample()

I'm trying to figure out exactly what the prob parameter in the sample function does. With the following code, does sample look randomly for the first possible sample--let's say it choses the second element--and then assess whether it can be chosen according to it's probability which is 0