Hi Satish,
Pascal's suggestion is better.
Please use ?dput() to show the example data.
op <- options(digits.secs=6)
library(zoo)
##added a couple more rows
dat <- read.zoo(text="V1 V2 V3 V4 V5 V6
'2014-03-14 22:41:46.988804' 10 2 8 3 14
'2014-03-14 22:41:46.991126' 13 4 9 5 15
Hi,
You could also try:
library(plyr)
ddply(mutate(sardat,sec=as.numeric(gsub(".*:(.*)\\..*$","\\1",sardat$V1))),.(sec),
numcolwise(mean))
# sec V2 V3 V4 V5 V6
#1 46 15.0 3.80 11.20 4.60 17.8
#2 47 14.28571 4.428571 9.857143 3.428571 16.85714
Hello,
Please have a look at the "xts" package.
Please don't post in HTML.
Regards,
Pascal
On Wed, Mar 19, 2014 at 12:26 AM, Satish Anupindi Rao
wrote:
> Hi,
> I have a zoo object with the first column as index. The columns have not been
> named yet... but that I can change. It looks like thi
On 03/19/2014 02:26 AM, Satish Anupindi Rao wrote:
Hi,
...
I would like to find the mean of the V2 to V6 columns on a per second interval.
Would anyone please be able to help me with a function and implementation for
that please?
Hi Satish,
If you don't care about the location of the interva
Hi,
I have a zoo object with the first column as index. The columns have not been
named yet... but that I can change. It looks like this :
V2 V3 V4 V5 V6
2014-03-14 22:41:46.988804 10 2 8 3 14
2014-03-14 22:41:46.991126 13 4 9
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