Hi:
On Wed, Jul 21, 2010 at 8:46 AM, vijaysheegi wrote:
>
> Hi R-community,
> I have the code as follows,i Fitted model as follows
> lbeer<-log(beer_monthly)
> t<-seq(1956,1995.2,length=length(beer_monthly)) #beer_monthly contains 400+
> entries
>
This is unnecessary:
> t2=t^2
> beer_fit_parab
Hi R-community,
I have the code as follows,i Fitted model as follows
lbeer<-log(beer_monthly)
t<-seq(1956,1995.2,length=length(beer_monthly)) #beer_monthly contains 400+
entries
t2=t^2
beer_fit_parabola=lm(lbeer~t+t2)
Below is not working for me.
Please help me in preparing the new data set for t
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