Hi,
But i didn't understand why you did it like this qnorm(40/200)??
I already found the answer qnorm(.20,181,7.3) and qnorm(.80,181,7.3)
Thanks.
On Mon, Aug 2, 2010 at 12:33 AM, Arun.stat wrote:
>
> try
> qnorm(40/200)
> --
> View this message in context:
> http://r.789695.n4.nabble.com/He
Also note that you can 'switch' tails via the argument lower.tail. By
default, it is TRUE.
> qnorm(p = .20, mean = 181, sd = 7.3, lower.tail = TRUE)
[1] 174.8562
> qnorm(p = .20, mean = 181, sd = 7.3, lower.tail = FALSE)
[1] 187.1438
Cheers,
Josh
On Sun, Aug 1, 2010 at 4:04 PM, Arun Kumar Saha
I gave you hint only, however whatever you done is correct.
On Mon, Aug 2, 2010 at 4:30 AM, n.a.s wrote:
> Hi,
>
> But i didn't understand why you did it like this qnorm(40/200)??
>
> I already found the answer qnorm(.20,181,7.3) and qnorm(.80,181,7.3)
>
>
> Thanks.
>
>
> On Mon, Aug 2, 2010 a
n.a.s gmail.com> writes:
>
> Hi , can any one help in this problem
>
> According to some study, the height for Northern European adult males is
> normally distributed with an average of 181 centimeter and a standard
> deviation of 7.3 centimeter. Suppose such an adult male is randomly chosen.
>
try
qnorm(40/200)
--
View this message in context:
http://r.789695.n4.nabble.com/Help-normal-distribution-tp2309730p2309735.html
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Hi , can any one help in this problem
According to some study, the height for Northern European adult males is
normally distributed with an average of 181 centimeter and a standard
deviation of 7.3 centimeter. Suppose such an adult male is randomly chosen.
Let X be height of that person. The nex
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