Re: [R] Fwd: Segment out of the Graph

2011-08-26 Thread Claudio Zanettini
Thanks I substituted points(inactT, inactR, pch="|") with rug(inactT, side=1, ticksize = 0.03) and now it is perfect Thanks again. Claudio 2011/8/26 David Winsemius > > On Aug 26, 2011, at 11:31 AM, heverkuhn wrote: > > >> No attachment. No code. >> >> I apology for that. I provided below t

Re: [R] Fwd: Segment out of the Graph

2011-08-26 Thread David Winsemius
On Aug 26, 2011, at 11:31 AM, heverkuhn wrote: No attachment. No code. I apology for that. I provided below the code and the vectors, Whatever that mean. Perhaps it means "below"? Yes, below, I mean out of the axis... And I think, that as you suggested, the xpd is what I was looking for.

Re: [R] Fwd: Segment out of the Graph

2011-08-26 Thread heverkuhn
No attachment. No code. I apology for that. I provided below the code and the vectors, Whatever that mean. Perhaps it means "below"? Yes, below, I mean out of the axis... And I think, that as you suggested, the xpd is what I was looking for. I need something like this http://www.springerima

Re: [R] Fwd: Segment out of the Graph

2011-08-25 Thread David Winsemius
On Aug 25, 2011, at 2:06 PM, Claudio Zanettini wrote: -- Forwarded message -- From: Claudio Zanettini Date: 2011/8/25 Subject: Re: [R] Segment out of the Graph To: David Winsemius Thanks David and Michael, In attachment there is one of the graph. No attachment. No code.

[R] Fwd: Segment out of the Graph

2011-08-25 Thread Claudio Zanettini
-- Forwarded message -- From: Claudio Zanettini Date: 2011/8/25 Subject: Re: [R] Segment out of the Graph To: David Winsemius Thanks David and Michael, In attachment there is one of the graph. the line below the graph is not related to the y label. I draw it at y= -10 just beco