Hi Rui and Ivan,Thank you explain of the code for me in detail. This is very
helpful. And the code works well now.Happy Holiday,Kai
On Wednesday, December 22, 2021, 02:30:49 PM PST, Rui Barradas
wrote:
Hello,
y[i] and c[i] are character strings, they are not variables of data set mpg.
Hello,
There's a stupid typo in my previous post. Inline
Às 22:30 de 22/12/21, Rui Barradas escreveu:
Hello,
y[i] and c[i] are character strings, they are not variables of data set
mpg.
To get the variables, use, well, help("get").
Note that I have changed the temp dir to mine. So I created
Hello,
y[i] and c[i] are character strings, they are not variables of data set mpg.
To get the variables, use, well, help("get").
Note that I have changed the temp dir to mine. So I created a variable
to hold the value
tmpdir <- "c:/temp/"
for (i in seq(nrow(mac))){
mpg %>%
filter(hwy
strange, I got error message when I run again:
Error: unexpected symbol in:
" geom_point()
ggsave"
> }
Error: unexpected '}' in "}"
On Wednesday, December 22, 2021, 10:18:56 AM PST, Kai Yang
wrote:
Hello Eric, Jim and Ivan,
Many thanks all of your help. I'm a new one in R area. I
Hello Eric, Jim and Ivan,
Many thanks all of your help. I'm a new one in R area. I may not fully
understand the idea from you. I modified my code below, I can get the plots
out with correct file name, but plots are not using correct fields' name. it
use y[i], and c[i] as variables' name, does
On Wed, 22 Dec 2021 16:58:18 + (UTC)
Kai Yang via R-help wrote:
> mpg %>% filter(hwy <35) %>% ggplot(aes(x = displ, y = y[i],
> color = c[i])) + geom_point()
Your code relies on R's auto-printing, where each line of code executed
at the top level (not in loops or functions) is run
You may have to add an explicit 'print' to ggplot
library(ggplot2)
library(tidyverse)
y <- c("hwy","cty")
c <- c("cyl","class")
f <- c("hwy_cyl","cty_class")
mac <- data.frame(y,c,f)
for (i in nrow(mac)){
mpg %>%filter(hwy <35) %>%
print(ggplot(aes(x = displ, y = y[i], color = c[i])) +
Try replacing
"c:/temp/f[i].jpg"
with
paste0("c:/temp/",f[i],".jpg")
On Wed, Dec 22, 2021 at 7:08 PM Kai Yang via R-help
wrote:
> Hello R team,I want to use for loop to generate multiple plots with 3
> parameter, (y is for y axis, c is for color and f is for file name in
> output). I created a
nrow() is just the numbers of rows in your data frame, use seq_len(nrow())
or seq(nrow()) to loop through all row numbers
On Wed, Dec 22, 2021, 12:08 Kai Yang via R-help
wrote:
> Hello R team,I want to use for loop to generate multiple plots with 3
> parameter, (y is for y axis, c is for color a
Hello R team,I want to use for loop to generate multiple plots with 3
parameter, (y is for y axis, c is for color and f is for file name in output).
I created a data frame to save the information and use the information in for
loop. I use y[i], c[i] and f[i] in the loop, but it seems doesn't wor
On Nov 10, 2012, at 10:17 PM, dae wrote:
> Thanks. That got me the answer.
Good. That's what the FAQ is for. You should also read the Posting Guide where
the reasons behind the request to include context for replies is laid out.
> This works:
>
> symbols = c("IEF","SPY")
>
> getSymbols(sym
Thanks. That got me the answer. This works:
symbols = c("IEF","SPY")
getSymbols(symbols)
for(symbol in symbols) {
assign(symbol, to.monthly(get(symbol), indexAt="endof"))
}
#end
--
View this message in context:
http://r.789695.n4.nabble.com/For-loop-question-tp4649215p46492
On Nov 10, 2012, at 2:36 PM, dae wrote:
> I have this code:
> IEF <- to.monthly(IEF, indexAt="endof")
> SPY <- to.monthly(SPY, indexAt="endof")
>
> I would like to use a for loop instead of separate entries,
> so the only code that needs to be modified is the list
> of symbols.
>
> symbols <- c
I have this code:
IEF <- to.monthly(IEF, indexAt="endof")
SPY <- to.monthly(SPY, indexAt="endof")
I would like to use a for loop instead of separate entries,
so the only code that needs to be modified is the list
of symbols.
symbols <- c("IEF", "SPY")
for(symbol in symbols) {
symbol <- to.m
> I will post data probably tonight, but here is my problem. I have
> preformed an MDS on a set of data. I have the scores of the four axes
> that
> are the optimal solution. I want to calculate the euclidean distance
> between time steps of the ordination.
See ?dist for a much faster sol
Actually, help.search("for") finds
Control(base) Control Flow
which is exactly where 'for' is documented. In general, if you want
the manual page of reserved words, then you'll have to quote them:
?"for"
Gabor
On Wed, Oct 1, 2008 at 3:39 PM, stephen sefick <[EMAIL PROTECTED]> wrote:
One must write ?"for" presumably since for is a reserved word in R.
On Wed, Oct 1, 2008 at 9:39 AM, stephen sefick <[EMAIL PROTECTED]> wrote:
> ?for doesn't return anything help.search("for") doesn't return anything-
> Is the for loop so prevelant in computer programing that the
> documentation is
?for doesn't return anything help.search("for") doesn't return anything-
Is the for loop so prevelant in computer programing that the
documentation is implicit or is R paradigm to discourage the use of
the for loop.
I will post data probably tonight, but here is my problem. I have
preformed an MD
Consider using a 'list' instead of creating a lot of objects that you then
have to manage:
x <- lapply(1:length(stats$hour), function(.indx) dataset[.indx, 3:15])
You can then access the data as x[[1]], ...
On Tue, May 20, 2008 at 12:58 PM, Douglas M. Hultstrand <
[EMAIL PROTECTED]> wrote:
> He
Take a look at ?assign
Juan Manuel Barreneche wrote:
I had to do the same thing many times, i usually use a combination of the
functions "eval", "parse" and "sprinf", as below:
k <- 1
for (i in 1:length(stats$hour)) {
eval(parse(text=sprintf("x%s <- dataset[%s,(3:15)]", i, k)))
k <- k+1
I had to do the same thing many times, i usually use a combination of the
functions "eval", "parse" and "sprinf", as below:
k <- 1
for (i in 1:length(stats$hour)) {
eval(parse(text=sprintf("x%s <- dataset[%s,(3:15)]", i, k)))
k <- k+1
}
what it does is:
eval(parse(text=STRING)) is a way to
Douglas -
To answer your question directly, use perhaps combination of ?assign and
?paste.
In general, you usually do not have to do this sort of thing, but can
use one of the apply family of functions (apply, sapply, lapply, mapply)
to do whatever you want with shorter, cleaner code and few
Hello,
I am trying to assign a variable name (x1,x2,x3...) in a loop statement
that is based on a counter (counter is based on the number of hours
within the datafile). The x1,x2 data will later be called for plotting
the data. Below is a clip of the for loop I am using, any suggestions?
k
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