gmail.com> writes:
>
> Hello all. This is likely to be a silly question, but I have a set of
> data points and I want to fit a curve to it, like this:
> http://www.igc.usp.br/pessoais/guano/temp/curve.png
While you could use a loess-curve, interpreting the rising branch a the
end is probably c
On 7/10/2008, at 2:53 PM, Carlos Guâno Grohmann wrote:
Hello all. This is likely to be a silly question, but I have a set of
data points and I want to fit a curve to it, like this:
http://www.igc.usp.br/pessoais/guano/temp/curve.png.
which function should I use?
Have a look at smooth.spline(
Hello all. This is likely to be a silly question, but I have a set of
data points and I want to fit a curve to it, like this:
http://www.igc.usp.br/pessoais/guano/temp/curve.png.
which function should I use?
many thanks
Carlos
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Statistical Data Center
Intermountain Healthcare
[EMAIL PROTECTED]
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> -Original Message-
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of Shirin Safa
> Sent: Tuesday, July 01, 2008 2:28 PM
> To: stephen sefick
> Cc: r-help@r-project.org
> There is an integrate.xy in sfsmic. Limitations discussed there.
Also see trap.rule in Hmisc
Vikas
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no this is not what I want.
I was using "loess" function or smooth.spline.
but For loess I don't know how would I be able to get the integral.
On 7/1/08, stephen sefick <[EMAIL PROTECTED]> wrote:
>
> ?lm
> lm(x[,1]~x[,2])
>
> On Tue, Jul 1, 2008 at 2:28 PM, Shirin Safa <[EMAIL PROTECTED]> wrote:
And, oddly enough :-), integrate.xy does pretty much exactly what I
suggested. Thanks for providing that reference
I would be interested in seeing how the original poster's data works
out using integrate.xy as opposed to simply calculating x*y
By the way, since the original data were 'perc
There is an integrate.xy in sfsmic. Limitations discussed there.
On Tue, Jul 1, 2008 at 6:27 PM, stephen sefick <[EMAIL PROTECTED]> wrote:
> I would like to know the answer to this question now that I know what we are
> getting at. integrate() looks like it is the right thing, but it has to use
I would like to know the answer to this question now that I know what we are
getting at. integrate() looks like it is the right thing, but it has to use
a function- I would like to know how to just integrate the area under a
curve with just an input of x and y coordinates.
Stephen
On Tue, Jul 1
I think the previous answer (to use lm() ) is not necessarily the best
option.
Since what you want is the definite integral (area under the curve), you
can just use one of the existing definite integration tools (sorry, I
don't recall the names because I don't use them).
If you want to get a
does loess return the values that it produces- take that and then integrate
under the curve.
On Tue, Jul 1, 2008 at 4:28 PM, Shirin Safa <[EMAIL PROTECTED]> wrote:
> no this is not what I want.
> I was using "loess" function or smooth.spline.
> but For loess I don't know how would I be able to ge
?lm
lm(x[,1]~x[,2])
On Tue, Jul 1, 2008 at 2:28 PM, Shirin Safa <[EMAIL PROTECTED]> wrote:
> Hi
>
> I have a set of data like this:
>
>*Time of Day* *Pct of Daily Volume* 9:45 7.50% 10 6.25% 10:15 4.45%
> 10:30 4.80% 10:45 4.45% 11:00 4.20% 11:15 2.50% 11:30 2.30% 11:45 2.25%
> 12:00 2.45% 12
Hi
I have a set of data like this:
*Time of Day* *Pct of Daily Volume* 9:45 7.50% 10 6.25% 10:15 4.45%
10:30 4.80% 10:45 4.45% 11:00 4.20% 11:15 2.50% 11:30 2.30% 11:45 2.25%
12:00 2.45% 12:15 2.60% 12:30 2.00% 12:45 2.05% 13:00 2.40% 13:15 1.90%
13:30 3.10% 13:45 2.90% 14:00 2.80% 14:15 2.50
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