Yes you are right, I want the sum. I wll change the formula accordingly.
On Fri, Oct 12, 2018 at 10:36 AM Jeff Newmiller
wrote:
> You said "add up"... so you did not mean to say that? Denes computed the
> mean...
>
> On October 11, 2018 3:56:23 PM PDT, roslinazairimah zakaria <
> roslina...@gmai
Here is a base R solution:
"dat" is the data frame as in Robert's solution.
> aggregate(dat[,3:6], by= dat[1], FUN = sum, na.rm = TRUE)
STUDENT_ID PO1M PO1T PO2M PO2T
1AA15285 287.80 350 37 50
2AA15286 240.45 330 41 50
Cheers,
Bert
Bert Gunter
"The trouble with having an
On 10/11/2018 5:12 PM, roslinazairimah zakaria wrote:
Dear r-users,
I have this data:
structure(list(STUDENT_ID = structure(c(1L, 1L, 1L, 1L, 1L, 1L,
2L, 2L, 2L, 2L, 2L), .Label = c("AA15285", "AA15286"), class = "factor"),
COURSE_CODE = structure(c(1L, 2L, 5L, 6L, 7L, 8L, 2L, 3L,
Dear r-users,
I have this data:
structure(list(STUDENT_ID = structure(c(1L, 1L, 1L, 1L, 1L, 1L,
2L, 2L, 2L, 2L, 2L), .Label = c("AA15285", "AA15286"), class = "factor"),
COURSE_CODE = structure(c(1L, 2L, 5L, 6L, 7L, 8L, 2L, 3L,
4L, 5L, 6L), .Label = c("BAA1113", "BAA1322", "BAA2113"
On 10/12/2018 08:58 AM, Dénes Tóth wrote:
On 10/12/2018 04:36 AM, Jeff Newmiller wrote:
You said "add up"... so you did not mean to say that? Denes computed
the mean...
Nice catch, Jeff. Of course I wanted to use 'sum' instead of 'mean'.
Oh, and one more note: If you have NAs in your co
On 10/12/2018 04:36 AM, Jeff Newmiller wrote:
You said "add up"... so you did not mean to say that? Denes computed the mean...
Nice catch, Jeff. Of course I wanted to use 'sum' instead of 'mean'.
On October 11, 2018 3:56:23 PM PDT, roslinazairimah zakaria
wrote:
Hi Denes,
It works pe
Yes, I thought that as well and had worked out this but didn't send it:
add_Pscores<-function(x) {
return(sum(unlist(x),na.rm=TRUE))
}
by(rzdf[,c("PO1M", "PO1T", "PO2M", "PO2T")],rzdf$STUDENT_ID,FUN=add_Pscores)
rzdf$STUDENT_ID: AA15285
[1] 724.8
---
You said "add up"... so you did not mean to say that? Denes computed the mean...
On October 11, 2018 3:56:23 PM PDT, roslinazairimah zakaria
wrote:
>Hi Denes,
>
>It works perfectly as I want!
>
>Thanks a lot.
>
>On Fri, Oct 12, 2018 at 6:29 AM Dénes Tóth
>wrote:
>
>>
>>
>> On 10/12/2018 12:12 A
Hi Denes,
It works perfectly as I want!
Thanks a lot.
On Fri, Oct 12, 2018 at 6:29 AM Dénes Tóth wrote:
>
>
> On 10/12/2018 12:12 AM, roslinazairimah zakaria wrote:
> > Dear r-users,
> >
> > I have this data:
> >
> > structure(list(STUDENT_ID = structure(c(1L, 1L, 1L, 1L, 1L, 1L,
> > 2L, 2L, 2
On 10/12/2018 12:12 AM, roslinazairimah zakaria wrote:
Dear r-users,
I have this data:
structure(list(STUDENT_ID = structure(c(1L, 1L, 1L, 1L, 1L, 1L,
2L, 2L, 2L, 2L, 2L), .Label = c("AA15285", "AA15286"), class = "factor"),
COURSE_CODE = structure(c(1L, 2L, 5L, 6L, 7L, 8L, 2L, 3L,
Dear r-users,
I have this data:
structure(list(STUDENT_ID = structure(c(1L, 1L, 1L, 1L, 1L, 1L,
2L, 2L, 2L, 2L, 2L), .Label = c("AA15285", "AA15286"), class = "factor"),
COURSE_CODE = structure(c(1L, 2L, 5L, 6L, 7L, 8L, 2L, 3L,
4L, 5L, 6L), .Label = c("BAA1113", "BAA1322", "BAA2113",
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