Re: [R] Extracting matched expressions

Thanks Jim - it's not elegant, but it works. Instead of using space as a delimiter, I used "\u001E" - it's the unicode record delimiter character, and I figure there's less chance of a clash with a character in the match. Hadley On Sun, Nov 8, 2009 at 1:40 PM, jim holtman wrote: > Is this what

Re: [R] Extracting matched expressions

strapply in the gsubfn package can do that. It applies the indicated function, here just c, to the back references from the pattern match and then simplifies the result using simplify. (If you omit simplify here it would give a one element list like strsplit does.) library(gsubfn) pat <- "(.*?) (.

Re: [R] Extracting matched expressions

Is this what you want: > x <- ' one two three ' > y <- > sub(".*?([^[:space:]]+)[[:space:]]+([^[:space:]]+)[[:space:]]+([ehrt]{5}).*", + "\\1 \\2 \\3", x, perl=TRUE) > unlist(strsplit(y, ' ')) [1] "one" "two" "three" On Sun, Nov 8, 2009 at 1:51 PM, Hadley Wickham wrot

[R] Extracting matched expressions

Hi all, Is there a tool in base R to extract matched expressions from a regular expression? i.e. given the regular expression "(.*?) (.*?) ([ehtr]{5})" is there a way to extract the character vector c("one", "two", "three") from the string "one two three" ? Thanks, Hadley -- http://had.co.nz/