Thanks a lot!! It sure helped.
and many thanks to all other repliers!
On Tue, Aug 24, 2010 at 3:40 PM, Dimitris Rizopoulos <
d.rizopou...@erasmusmc.nl> wrote:
> try something like this:
>
> n <- 23
> x <- array(1:20, dim = c(n, 6))
> huge.list <- rep(list(x), 1000)
>
> out <- lapply(1:4, functio
On Aug 24, 2010, at 11:29 AM, Vladimir Mikryukov wrote:
> Dear list members,
>
> I need to create a table from a huge list object,
> this list consists of matrices of the same size (but with different
> content).
>
> The resulting n tables should contain the same rows from all matrices.
>
> Fo
try something like this:
n <- 23
x <- array(1:20, dim = c(n, 6))
huge.list <- rep(list(x), 1000)
out <- lapply(1:4, function (i) {
t(sapply(huge.list, "[", i = i, j = 1:6))
})
out[[1]]
out[[4]]
I hope it helps.
Best,
Dimitris
On 8/24/2010 11:29 AM, Vladimir Mikryukov wrote:
Dear list
Dear list members,
I need to create a table from a huge list object,
this list consists of matrices of the same size (but with different
content).
The resulting n tables should contain the same rows from all matrices.
For example:
n <- 23
x <- array(1:20, dim=c(n,6))
huge.list <- list()
for (i
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