oun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of muzammil786
> Sent: Wednesday, November 14, 2012 12:12 PM
> To: r-help@r-project.org
> Subject: Re: [R] R exponential regression
>
> I am having a similar problem on this data (given below). I have tried
>
if you could guide me what's wrong here.
Cheers.
Muzammil
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---
Date: Sun, 10 Jan 2010 16:44:02 -0500
From: "Murray Cooper"
To: "chrisli1223" ,
Subject: Re: [R] R exponential regression
Message-ID: <1fa457dc6fe04de4ab2541d89d2d0...@ownerc86c2419d>
Content-Type:
chrisli1223 wrote:
Hi all,
I have a dataset which consists of 2 columns. I'd like to plot them on a x-y
scatter plot and fit an exponential trendline. I'd like R to determine the
equation for the trendline and display it on the graph.
Here's one way:
f <- function(x,a,b) {a * exp(b * x)}
#
nd follow the rest
> of the procedure described in 1).
>
> Hope this helps.
>
> Murray M Cooper, Ph.D.
> Richland Statistics
> 9800 N 24th St
> Richland, MI, USA 49083
> Mail: richs...@earthlink.net
>
> - Original Message -
> From: "chrisli1223&q
.@earthlink.net
- Original Message -
From: "chrisli1223"
To:
Sent: Thursday, January 07, 2010 10:33 PM
Subject: [R] R exponential regression
Hi all,
I have a dataset which consists of 2 columns. I'd like to plot them on a
x-y
scatter plot and fit an exponential trendlin
is will
be greatly appreciated.
Many thanks,
Chris
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I am reasonably sure that the log link with a zero intercept
duplicates your efforts with nls().
Take a look at this:
> txt <- "X Y
+ 2 2.927064
+ 5 14.6582
+ 4 8.567706
+ 3 5.007817
+ 1 1.710867
+ 6 25.07823
+ 4 8.567706
+ 7
[EMAIL PROTECTED]
Hello
First I want to implement exponential regression in R, with out constant for
the following formula.
Y = exp(a*X)
‘a’ is coefficient I wanted to determine. That I could do also in SPSS but my
question is rather to estimate the ‘standard error of Ŷi at each Xi. This
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