On Oct 21, 2010, at 8:39 AM, Petr PIKAL wrote:
Hi
fjsan...@gmail.com napsal dne 21.10.2010 12:44:30:
Hi Petr, thanks for your help.
My array has four dimensions. My problem is the next:
library(survival)
initial <- array(rnorm(120),c(40,30,20,50))
final <- array(0,
dim=c(dim(initial)[
On Oct 21, 2010, at 4:40 AM, Francisco Javier Santos Alamillos wrote:
Dear R community,
I am working with huge arrays, so I spend a lot of time computing.
This is
my code:
for (x in 1:dim(variable)[1]){
for (y in 1:dim(variable)[2]){
for (z in 1:dim(variable)[3]){
resu
Hi
fjsan...@gmail.com napsal dne 21.10.2010 12:44:30:
> Hi Petr, thanks for your help.
>
> My array has four dimensions. My problem is the next:
>
> library(survival)
> initial <- array(rnorm(120),c(40,30,20,50))
> final <- array(0,
dim=c(dim(initial)[1],dim(initial)[2],dim(initial)[3]))
>
Dear R community,
I am working with huge arrays, so I spend a lot of time computing. This is
my code:
for (x in 1:dim(variable)[1]){
for (y in 1:dim(variable)[2]){
for (z in 1:dim(variable)[3]){
result <- max(variable[x,y,z,])
}
}
}
Is there a more efficient p
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