On Mon, May 17, 2010 at 11:12 AM, jim holtman wrote:
> ?'[['
>
> What I think you want is:
>
> x <- "V1_1"
> mean(l[[x]])
>
> Also you need to look at 'get'.
...and if the answer is get() or assign() you should usually consider
library("fortunes"); fortune("rethink the question");
/Henrik
>
> O
?'[['
What I think you want is:
x <- "V1_1"
mean(l[[x]])
Also you need to look at 'get'.
On Mon, May 17, 2010 at 4:41 AM, Stefan Petersson <
stefan.peters...@inizio.se> wrote:
>
> I'm trying to dynamically build variable names to use on a list. Let's say
> I have a list like this one:
>
> l <-
>
>
> I'm trying to dynamically build variable names to use on a list. Let's say I
have a list like this one:
>
> l <- list(V1_1=c(1,2,3), V1_2=c('One','Two','Three'))
>
> And I succesfully build my variable name like this:
>
> paste('l$', 'V1_1', sep='')
>
> Why can't I just run a mean call
> library(fortunes)
> fortune('parse')
If the answer is parse() you should usually rethink the question.
-- Thomas Lumley
R-help (February 2005)
>
On Mon, May 17, 2010 at 5:08 AM, Stefan Petersson <
stefan.peters...@inizio.se> wrote:
> >
> >
> > I'm trying to dynamically build variabl
I'm trying to dynamically build variable names to use on a list. Let's say I
have a list like this one:
l <- list(V1_1=c(1,2,3), V1_2=c('One','Two','Three'))
And I succesfully build my variable name like this:
paste('l$', 'V1_1', sep='')
Why can't I just run a mean call with the pasted variab
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