Are you the oswi who just asked a very similar question?
Regardless, as Josh said, the high-performance way to do this is to
use the specialty C code available through the xts package and the
to.period() functions, specifically to.minutes5
Michael
On Tue, May 8, 2012 at 8:48 AM, Milan Bouchet-Va
Le mardi 08 mai 2012 à 10:44 +0200, osvald wiklander a écrit :
>
>
>
> Hi everybody, I am sorry that I am kind of spamming this forum, but I
> have searched for some input everywhere and cant really find a nice
> solution for my problem.
>
> Data looks like:
>
>
Hi everybody, I am sorry that I am kind of spamming this forum, but I have
searched for some input everywhere and cant really find a nice solution for my
problem.
Data looks like:
price
2011-11-01 08:00:00 0.0
2011-11-01 08:00:00 0.0
2011
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