Hi Rich,
I do not know what u really want, because it seems to me, u want to calculate
the mean of all rows, where the chemical is Arsenic??
But try this to get a little more inside:
mean(chemdata$quant[chemdata$param=="Arsenic"])
The vector chemdata[chemdata$param=="Arsenic",] is a logical ve
On Tue, 30 Aug 2011, David Winsemius wrote:
That does look more workable. You might consider changing the dates with:
chemadata$samp_date <- as.Date(as.character(chemdata$sample_date) )
David,
I was thinking that I needed to do this. Thank you. It's now done.
Good progress for the first
On Aug 30, 2011, at 5:38 PM, Rich Shepard wrote:
On Tue, 30 Aug 2011, David Winsemius wrote:
I think you need to go back and do your input operations again with
sep="|"
David,
Yes, that's better. I did not know of the sep option. The new
results:
str(chemdata)
'data.frame': 14886
On Tue, 30 Aug 2011, David Winsemius wrote:
I think you need to go back and do your input operations again with
sep="|"
David,
Yes, that's better. I did not know of the sep option. The new results:
str(chemdata)
'data.frame': 14886 obs. of 4 variables:
$ site_id: Factor w/ 148 le
On Aug 30, 2011, at 5:30 PM, Rich Shepard wrote:
On Tue, 30 Aug 2011, David Winsemius wrote:
It appears that your original file was delimited by "|" and your
used something else, perhaps the default white-space setting?
David,
Yes, the csv file separator is the pipe.
It is _not_ a csv
On Tue, 30 Aug 2011, David Winsemius wrote:
It appears that your original file was delimited by "|" and your used
something else, perhaps the default white-space setting?
David,
Yes, the csv file separator is the pipe.
I think you need to go back and do your input operations again with
se
On Wed, 31 Aug 2011, Tal Galili wrote:
It is a bit hard to read the "summary" you are using. Consider please
pasting the output of:
ls.str(chemdata)
Tal,
Yes, summary() is inappropriate. I do want str() instead. And what that
shows is:
str(chemdata)
'data.frame': 14886 obs. of 1 vari
On Aug 30, 2011, at 5:00 PM, Rich Shepard wrote:
I don't find how to do what I need to do in Dalgaard or 'R
Cookbook', so
I'm asking here.
I have a data frame with water chemistry data and I want to start
exploring these data. There are three factors (site, date, chemical)
associated with
Hi Rich,
It is a bit hard to read the "summary" you are using. Consider please
pasting the output of:
ls.str(chemdata)
Regarding your question, please start and see if this work (I'm not sure,
since it seems you have made some changes to the summary output, and I am
only guessing how things look
I don't find how to do what I need to do in Dalgaard or 'R Cookbook', so
I'm asking here.
I have a data frame with water chemistry data and I want to start
exploring these data. There are three factors (site, date, chemical)
associated with each measurement. The data frame looks like this:
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