txt <- paste( nm, '<-', tmp, sep='' )
eval( parse(text=txt), parent.frame() )
in `foo()` will do the trick.
Yuck.
If you use that sort of syntax your code becomes hard to understand and
you risk changing variables that users do not want changed. When the
use uses somethi
Thanks, Bill, I should have googled more carefully:
http://stackoverflow.com/questions/9561053/assign-values-to-a-list-element-in-r
So, remove
assign(nm, tmp, parent.frame())
and add
txt <- paste( nm, '<-', tmp, sep='' )
eval( parse(text=txt), parent.frame() )
in `foo(
You could use a 'replacement function' named 'bar<-', whose last argument
is called 'value', and use bar(variable) <- newValue where you currently
use foo(variable, newValue).
bar <- function(x) {
x + 3
}
`bar<-` <- function(x, value) {
bar(value)
}
a <- NA
bar(a) <- 4
a
# [1] 7
b <- list
Hello,
When I use function `foo` with list elements (example 2), it defines a new
object named `b[[1]]`, which is not what I want. How can I change the function
code to show the desired behaviour for all data structures passed to the
function? Or is there a more appropriate way to sort of "pa
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