Ha, sorry for the obtuseness Rolf. New to this. Thanks for your help.
-Steve
> On Mar 8, 2015, at 9:25 PM, Rolf Turner [via R]
> wrote:
>
> Rolf Turner
--
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On 09/03/15 07:27, Steven Archambault wrote:
My date column is the excel numeric date format. For instance, in
excel, that first date is 11 September 2012.
And we were supposed to know that? The level of obtuseness of people
who post to this list truly knows no lower bound.
Be that as it ma
... and that is the source of your difficulties, as I and others have told you.
-- Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
"Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom."
Clifford Stoll
On Sun, Mar 8, 2015 at 11:27 A
My date column is the excel numeric date format. For instance, in excel, that
first date is 11 September 2012.
On Mar 8, 2015, at 10:41 AM, Frederic Ntirenganya wrote:
> Hi Steve,
>
> Can you please explain to us your date column? thanks.
>
> Regards,
> Fredo.
> On Mar 8, 2015 7:32 PM, "Steve
The Ecfun package includes a function "as.Date1970", that merely
provides a default origin for "as.Date".
This kind of thing can be found using
library(sos)
findFn('as.Date1970')
This produced a list in my default browser showing 4 links in 3
packages, the first 2 of whic
Please read ?as.Date carefully. Your argument appears to be numeric
(??) and you do not seem to have specified an origin:
"as.Date will accept numeric data (the number of days since an epoch),
but only if origin is supplied."
Cheers,
Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 46
Hi Steve,
Can you please explain to us your date column? thanks.
Regards,
Fredo.
On Mar 8, 2015 7:32 PM, "Steve Archambault" wrote:
> Hi all,
>
> I am trying in vain to create a new object "Year" in my data frame from
> existing Date data. I have tried many different approaches, but can't seem
Hi all,
I am trying in vain to create a new object "Year" in my data frame from
existing Date data. I have tried many different approaches, but can't seem
to get it to work. Here is an example of some code I tried.
date1<- as.Date(wells$Date,"%m/%d/%Y")
wells$year<-as.numeric(format(date1, "%Y"))
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