Re: [R] Data normalization

2013-04-06 Thread Rui Barradas
Hello, See ?scale scale(DATA) # mean 0, unit variance Hope this helps, Rui Barradas Em 06-04-2013 21:21, Beatriz González Domínguez escreveu: Dear all, I’m finding difficulties to normalize this data. Could you provide some input? DATA: c(0.000103113, 0.000102948, 0.000104001, 0.0001037

[R] Data normalization

2013-04-06 Thread Beatriz González Domínguez
Dear all, I’m finding difficulties to normalize this data. Could you provide some input? DATA: c(0.000103113, 0.000102948, 0.000104001, 0.000103794, 0.000104628, 9.2765e-05, 9.4296e-05, 9.5025e-05, 9.4978e-05, 9.8821e-05, 9.7586e-05, 9.6285e-05, 0.00010158, 0.000100919, 0.000103535, 0.00010332

Re: [R] data normalization

2012-06-21 Thread arun
1  3    3 0.6094344 0.7128677 12  3    5 0.6550063 0.7661741 A.K. - Original Message - From: york8866 To: r-help@r-project.org Cc: Sent: Tuesday, June 19, 2012 8:08 PM Subject: [R] data normalization I have a dataframe such like the following: ID    TIME    DV 1    0    0.88

Re: [R] data normalization

2012-06-20 Thread york8866
Thanks for the help, it works very well. -- View this message in context: http://r.789695.n4.nabble.com/data-normalization-tp4633939p4633964.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://s

Re: [R] data normalization

2012-06-20 Thread Dimitris Rizopoulos
assuming that the entries for each subject are ordered with respect to TIME and each subject has a measurement at TIME = 0, then you could use the following: Data <- read.table(textConnection("ID TIMEDV 1 0 0.880146038 1 1 0.88669051 1 3 0.610784702 1 5 0.75604 2 0

[R] data normalization

2012-06-20 Thread york8866
I have a dataframe such like the following: ID TIMEDV 1 0 0.880146038 1 1 0.88669051 1 3 0.610784702 1 5 0.75604 2 0 0.456263368 2 1 0.369991537 2 3 0.508798346 2 5 0.441037014 3 0