Hi Jim!
Thank you so much for the very helpful hints!!
I am learning 'split' now and it seems very useful..
HJ
On Tue, Mar 27, 2012 at 12:58 PM, jim holtman wrote:
> Why not use 'split' and get all the groups at once:
>
> result <- split(Calandra, list(Calandra$Day, Calandra$Season, drop = TRU
Why not use 'split' and get all the groups at once:
result <- split(Calandra, list(Calandra$Day, Calandra$Season, drop = TRUE)
On Tue, Mar 27, 2012 at 7:43 AM, Ivan Calandra
wrote:
> Hi HJ,
>
> Take a look at ?"&"; this is probably what you're looking for.
>
> What you could also do is:
> Calend
Hi HJ,
Take a look at ?"&"; this is probably what you're looking for.
What you could also do is:
Calender[Calender$Day=='Wd' & Calender$Season=="Winter", ] # notice the
last comma
This will subset directly without using which(); it might be helpful to you.
HTH,
Ivan
--
Ivan CALANDRA
Univer
Dear R-help,
My dataset (which is a data frame, called 'Calender' here) includes 365
rows representing 365 days for a year. One column ('Season')contains
factor data representing seasons, e.g. spring, summer, autumn and winter.
Another column (called 'Day') contains data representing wether the
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