Thanks, all!
I've tried changing the start and end of the loop and I tried cbind initial
column with the other columns to get the matrix I want. It did work! Thanks
also for the note about the parentheses. It real useful.
I'll try Oarray if that would fasten the iteration. Thanks again!
Deana
Fair enough -- hadn't thought of going the other way. I do remember
looking at that C trick once, but I'm actually somewhat surprised
Fortan has it natively: I had always associated multiple basing with
something like VBA that has to keep everyone on board but no one
happy. Seems a surprisingly fle
R. Michael Weylandt wrote:
>
> This may be an unnecessary aside, but other than obfuscating
> code or allowing people to never stop thinking in C and start
> thinking in R, what practical purpose would this package
> serve in an R context?
>
I'd think about constructs like
income[1990:2010]
This may be an unnecessary aside, but other than obfuscating code or
allowing people to never stop thinking in C and start thinking in R,
what practical purpose would this package serve in an R context?
Michael
On Mon, Oct 24, 2011 at 11:31 PM, Ben Bolker wrote:
> Md Desa, Zairul Nor Deana Binti
Md Desa, Zairul Nor Deana Binti ku.edu> writes:
>
> Hello,
> Does anyone knows how to deal with zero subscript in R.
Try the "Oarray" package (that's a capital letter "O").
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On Oct 24, 2011, at 7:23 PM, Md Desa, Zairul Nor Deana Binti wrote:
Hello,
Does anyone knows how to deal with zero subscript in R. I have this
code:
for (i in 1:nitems){
+ for (j in 1:ncat-1) {
+ draw<-matrix(rnorm(nitems*(ncat-1),seed1,seed2),nitems,
(ncat-1))
+
Hi Deana,
No, R does not deal with zero subscripts. Could it be done? Of
course. The simplest approach is: 0 + 1 = 1, which is the R
equivalent. You need to adjust your code to go, for example, from 1
to 30 instead of 0 to 29.
Cheers,
Josh
On Mon, Oct 24, 2011 at 4:23 PM, Md Desa, Zairul No
Hello,
Does anyone knows how to deal with zero subscript in R. I have this code:
for (i in 1:nitems){
+ for (j in 1:ncat-1) {
+ draw<-matrix(rnorm(nitems*(ncat-1),seed1,seed2),nitems,(ncat-1))
+ d<-( sigma_d*draw ) + mu_d
+ draw<-matrix(rtnorm((nitems*(ncat-1)
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