Dear Matteo,
I found a one-liner solution to this problem:
n <- 100
data.table(i0 = 100)[, (paste0("i", 1:n)) := 100]
the data.table(i0=100) creates a one column-one row data.table,
Between the [] brakets i create a column name vector with paste, and
surround it with () to make it recognised as n
Maybe there’s a cleverer way, but that’s what I can think off the top of my
head:
n <- 100
M.dt <- data.table(matrix(ncol = 100))
M.dt[] <- 100
names(M.dt) <- sapply(1:100, function(x) paste0("i", x))
The sapply is your loop.
> Am 16.12.2015 um 12:53 schrieb Matteo Richiardi :
>
> I apologise
Hi,
thanks a lot to everybody for your help. Very nice suggestions!
Matteo
On 16 December 2015 at 12:53, Matteo Richiardi
wrote:
> I apologise for this very basic question, but I found no answers on the
> web.
> I want to create a data.table with n columns, named i1 ... i'n', with only
> one row
library(data.table)
dat <- as.data.table(matrix(100, nrow=1, ncol=100))
colnames(dat) <- gsub("V", "i", colnames(dat))
--
GG
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. But as I do not
know what you want to do with your data.table I may be completely out.
Cheers
Petr
> -Original Message-
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Matteo
> Richiardi
> Sent: Wednesday, December 16, 2015 12:53 PM
> To: r-help@r-pr
I apologise for this very basic question, but I found no answers on the web.
I want to create a data.table with n columns, named i1 ... i'n', with only
one row with value = 100 for every variable.
I can do it "by hand":
M.dt <- data.table(i1=100,i2=100,i3=100)
but I would like to make it in a lo
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