something like this should work:
> oldIDs <- c(1234, 1235, 1236)
> newIDs <- c(5000, 1234, 7000, 1236)
> # really new ones -- don't match the old ones
> (reallyNew <- setdiff(newIDs, oldIDs))
[1] 5000 7000
> # assign these back to the oldIDs for the next month
> (oldIDs <- c(oldIDs, reallyNew))
[1
A reproducible example would be useful, as yours isn't entirely clear.
But maybe something like this?
id.info <- data.frame(foreign=sort(unique(foreign.id)),
local=1:length(unique(foreign.id)))
and then use merge() to combine that with your actual data.
Sarah
On Tue, Sep 20, 2011 at 11:50 AM,
First off, let me apologize for the elementary question. I'm obviously a
novice.
Here's a stripped version of my problem.
March
foreign id = 1234, my id = 1
foreign id = 1235, my id = 2
foreign id = 1236, my id = 3
So we are adding new people for April, and things don't necessarily come in
order
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