Hello,
I believe this solves your problem
fun <- function(x){
f <- function(x, n){
if(length(x) < n) x <- c(x, rep(NA, n-length(x)))
return(x)
}
lapply(x, f, max(unlist(lapply(x, length
}
fun(result) # the 'result' list above
On Jan 8, 2012, at 2:28 PM, jim holtman wrote:
Is this what you are after:
The code below is essentially what I would have imagined to be a
method of programming "cbind.data.frame.fill". It's worth noting that
either reshape2 or plyr (I don't remember which) offer an rbind
version: rbin
Is this what you are after:
> more<-c('R is a free software environment for statistical computing',
+ 'It compiles and runs on a wide variety of UNIX platforms')
> result<-strsplit(more,' ')
> result
[[1]]
[1] "R" "is" "a" "free""software"
"environme
Hello everyone,
What is the most efficient & simpliest way to convert all components of a
list to separate columns in a matrix?
Is there an easy way to programmatically "pad" the length of the resulting
shorter character vectors so that they can be easily combined into a data
frame?
I have the f
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