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wdunlap tibco.com
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> Behalf
> Of Noah Silverman
> Sent: Monday, October 08, 2012 9:57 PM
> To: r-help
> Subject: [R] Convert COLON separated format
>
> I have a bunc
If you want something that is fast, read the file in, strip off the
colon/data, write it out to a temp and then read it back in. Here is
a 355K line file:
> temp <- tempfile()
> input <- readLines('/temp/colon.txt')
> length(input)
[1] 355212
> system.time(input <- gsub("(:[0-9]+)", "", input))
Hello,
Here's a function that doesn't do it all but might help.
fun <- function(x){
x1 <- unlist(strsplit(x, " "))
x2 <- x1[nchar(x1) > 0]
i <- as.integer(x2[1])
x3 <- unlist(strsplit(x2[-1], ":"))
j <- as.integer(x3[rep(c(TRUE, FALSE), length(x3)/2)])
y <- numeric(max(j)
Mr Silverman,
On 9 October 2012 00:56, Noah Silverman wrote:
> I have a bunch of data sets that were created for the libsvm tool. They
> are in "colon separated sparse format".
> Is there a simple way to do this?
>
Use read.table with a sep of ':' and let me know how you get on. -- H
--
Sent
I have a bunch of data sets that were created for the libsvm tool. They are in
"colon separated sparse format".
i.e.
1 5:1 27:3 345:10
Is a row with the label of "1" and only has values in columns 5, 27, and 345.
I want to read these into a data.frame in R.
Is there a simple way to do t
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