Hi Lydia,
Your question match more the topics of the r-sig-geo list.
Please have a look at the "raster" package, as well as the "rasterVis"
package to read and work with NetCDF format.
Regards,
Pascal
On Tue, May 13, 2014 at 6:27 AM, Lydia Keppler wrote:
> Hi all,
>
> I am using Windows 7 and
Granted, you are new here, but reading the Posting Guide is advice included in
every post on this list. One key recommendation found there is to not post in
HTML, as we don't see what you see when you do that. Use plain text email.
Another key piece of advice in the Posting Guide is to provide a
Well one would expect that you might find something useful by
searching the obvious, like
?contourplot
and following the links therein.
It also seems (to me, anyway) that you have made little effort to
understand how R works, its data structures, syntax, and so forth. So
please peruse "An Introd
Hi all,
I am using Windows 7 and R Studio version 3.0.2 (2013-09-25).
I am relatively new to R and am trying to make a contour plot from a 3D
data grid.
I my data file has the following specifics:
[1] "file Data.nc has 3 dimensions:"
[1] "time Size: 96"
[1] "lat Size: 21"
[1] "lon Size: 61
[mailto:r-help-boun...@r-project.org] On
> Behalf
> Of ivo welch
> Sent: Saturday, November 16, 2013 11:40 AM
> To: r-help
> Subject: [R] contour plot axis correspondence
>
> I am struggling with a contour plot. I want to place a cross over the
> minimum. alas, I don&#x
I am struggling with a contour plot. I want to place a cross over the
minimum. alas, I don't seem to be able to map axes appropriately.
here is what I mean:
N <- 1000
rm <- rnorm(N, mean=0.0, sd=0.4)
rx <- rnorm(N, mean=0.0, sd=0.4)
rt <- rnorm(N, mean=0.0, sd=0.4)
exploss <- function(hdgM,hdg
Thanks a lot, that is all i want. If someone is interessed, see the code
below
panel.3d.contour <-
function(x, y, z, rot.mat, distance,
nlevels = 20, zlim.scaled, ...) # les3 points de suspension
pour dire les autres paramètres sont ceux données par défaut
{
add.line <- trel
On May 16, 2013, at 8:23 AM, sms...@univ-fcomte.fr wrote:
> Hello folks,
>
> i'm a R beginner and i want to put in a same plot both contour lines and
> persp plot.
>
> For example,
>
> fn<-function(x,y){sin(x)+2*y} #this looks like a corrugated tin roof
>
> x<-seq(from=1,to=100,by=1) #genera
Hello folks,
i'm a R beginner and i want to put in a same plot both contour lines
and persp plot.
For example,
fn<-function(x,y){sin(x)+2*y} #this looks like a corrugated tin roof
x<-seq(from=1,to=100,by=1) #generates a list of x values to sample
y<-seq(from=1,to=100,by=1) #generates a list
On Oct 10, 2012, at 7:58 AM, namrata mohapatra wrote:
> Hello
>
> I am interested to plot a contour plot using the colour : rainbow , however I
> want to reverse the order of the colour ( such that red represents max value
> and blue min value) and also remove the lines in white in the plot .
Hello,
In the classical function "contour" labels are drawn so that each contour line
is broken at the place of the label, so that the label does not overlap the
line. In the trellis contoourplot the labels are placed beside or over the
line, controlled by the label.style parameter, but I could
As Duncan Murdoch pointed out, the example data frame that you provided
doesn't give very interesting results (all the shock values are zero), so
I created a different shock variable for illustration. I suggest using
the interp() function in the R package akima.
df <- structure(list(c = 1:6, z
On 12-07-19 2:01 AM, Akhil dua wrote:
Hello every one
can any one tell me how to draw contour with this data set
c zshock
1 0.45450237 0
2 0.02663337 0
3 -2.08444556 0
4 -0.12715275 0
5 0.67066360 0
6 -0.73540081 0
I want to dr
Hello every one
can any one tell me how to draw contour with this data set
c zshock
1 0.45450237 0
2 0.02663337 0
3 -2.08444556 0
4 -0.12715275 0
5 0.67066360 0
6 -0.73540081 0
I want to draw contour for shock i.e my z matrix is shock
Dear R users,
I am new to lattice but am trying to get to grips with it.
I need to add contour lines for the topography to a plot I created with spplot.
The topography is available as a
SpatialPixelsDataFrame object Z_sfc. If I plot it as spatial lines, after
converting to a SpatialLines objec
Hello,
Now I don't understand. Inline
Em 18-07-2012 11:56, Akhil dua escreveu:
why are you writing ncol=2 ?
I have levels=100 for x1 and the x1 is my z matrix
In your contour instruction x3 is the z matrix, not x1. And your dataset
shows a 2x3 grid, hence ncol=2, for (x1 times x2) 0:1x1:3.
Hi Akhil,
in addition to Rui's post, here is a solution using lattice graphics.
tmp<-read.table(textConnection("x1 x2 x3
0 12
0 21
0 35
1 14
1 22
1 33"),header=T)
library(lattice)
contourplot(x3~x1*x2,tmp)
hth.
Am 18.07.2012 11:23, schrieb Akhil dua:
> Hello
Hello,
Follow the code below and see what's the right way:
d <- read.table(text="
x1 x2 x3
0 12
0 21
0 35
1 14
1 22
1 33
", header=TRUE)
x3 <- matrix(d[, "x3"], ncol=2)
levels <- sort(unique(x3))
contour(0:1, 1:3, t(x3), levels=levels)
Hope this helps,
Ru
Hello Everyone
I have the data long format and I want to draw the contour plot with it
x1 x2 x3
0 12
0 21
0 35
1 14
1 22
1 33
when I am using contour(x1,x2,x3,col=heat.colors) or fill.contour
its giving me an error that increasing x and y expected
So please
Hi all,
As you know, spplot function of sp package is very powerful and even allows to
superimpose contour lines with the option 'contour=TRUE'. The color of the
contour line can be changed with the 'col' option. I'd like to know if it
possible to improve on this:
1) changing the color of the
On 12-04-21 9:21 PM, Stoch astic wrote:
First time user, so sorry if I don't understand protocol.. Anyway, I have
created a data frame consisting of pearson's R values at various x and y
coordinates and then plotted this using filled.contour. My data is similar
to fMRI data except that it is a su
The C implementation of the algorithm is here:
http://svn.r-project.org/R/trunk/src/main/plot3d.c
(grep filledcontour) but I don't see a reference other than to Ross Ihaka.
Hope this helps,
Michael
On Sat, Apr 21, 2012 at 9:21 PM, Stoch astic wrote:
> First time user, so sorry if I don't under
First time user, so sorry if I don't understand protocol.. Anyway, I have
created a data frame consisting of pearson's R values at various x and y
coordinates and then plotted this using filled.contour. My data is similar
to fMRI data except that it is a surface map reconstructed from
histological
I do agree with the recommendation to consider car::dataEllipse() for
plotting a best fit for the theoretical bivariate Normal situation.
However, the bagplot function from Has Peter Wold: http://www.wiwi.uni-bielefeld.de/~wolf/#software
is more likely to "line up" and be suitable for drawi
On 3/3/2012 12:34 PM, drflxms wrote:
Thanx a lot Greg for the hint and letting me not alone with this!
Tried ellipse and it works well. But I am looking for something more
precise. The ellipse fits the real border to the nearest possible
ellipse. I want the "real" contour, if possible.
The 'co
Please allow one (hopefully ;) last question:
Do you think the code I adopted from Hänggi is valid in selecting a
contour which encloses i.e. 68% of the scatter-plot data? - I am still
not completely shore... still looking for the reason of the different
result of Hänggis and Foresters code. Should
Puhh, I am really happy to read that the idea was not completely
sensless. This would have heavily damaged my anyway labile view of the
world of statistics ;)
In any case I need to get to know more about bivariate normal
distributions! Any literature recommendations?
Felix
Am 03.03.12 22:13, schr
Greg, extremely cool thoughts! Thank you for delving into it this deep.
As I mentioned, I am a neurologist with unfortunately poor statistical
training. You are professional statisticians. So I'd like to apologize
for any unprofessional nomenclature and strange thoughts beforehand.
As my previous
To further explain. If you want contours of a bivariate normal, then
you want ellipses. The density for a bivariate normal (with 0
correlation to keep things simple, but the theory will extend to
correlated cases) is proportional to exp( -1/2 ( x1^2/v1 + x2^2/v2 )
so a contour of the distributi
On Mar 3, 2012, at 20:25 , drflxms wrote:
> "Once you go into two dimensions, SD loses all meaning, and adding
> nonparametric density estimation into the mix doesn't help, so just stop
> thinking in those terms!"
>
> This makes me really think a lot! Is plotting the 0,68 confidence
> interval i
The key part of the ellipse function is:
matrix(c(t * scale[1] * cos(a + d/2) + centre[1], t * scale[2] *
cos(a - d/2) + centre[2]), npoints, 2, dimnames = list(NULL,
names))
Where (if I did not miss anything) the variable 't' is derived from a
chisquare distribution and the c
Wow, David,
thank you for these sources, which I just screened. bagplot looks most
promising to me. I found it in the package ‘aplpack’ as well as in the R
Graph Gallery
http://addictedtor.free.fr/graphiques/RGraphGallery.php?graph=112
Ellipses are not exactly what I am heading for. I am looking
Thank you very much for your thoughts!
Exactly what you mention is, what I am thinking about during the last
hours: What is the relation between the den$z distribution and the z
distribution.
That's why I asked for ecdf(distribution)(value)->percentile earlier
this day (thank you again for your qu
On Mar 3, 2012, at 12:34 PM, drflxms wrote:
Thanx a lot Greg for the hint and letting me not alone with this!
Tried ellipse and it works well. But I am looking for something more
precise. The ellipse fits the real border to the nearest possible
ellipse. I want the "real" contour, if possible.
On Mar 3, 2012, at 17:01 , drflxms wrote:
> # this is the critical block, which I still do not comprehend in detail
> z <- array()
> for (i in 1:n){
>z.x <- max(which(den$x < x[i]))
>z.y <- max(which(den$y < y[i]))
>z[i] <- den$z[z.x, z.y]
> }
As far as I can tell, the po
Thanx a lot Greg for the hint and letting me not alone with this!
Tried ellipse and it works well. But I am looking for something more
precise. The ellipse fits the real border to the nearest possible
ellipse. I want the "real" contour, if possible.
Meanwhile I found an interesting function named
Look at the ellipse package (and the ellipse function in the package)
for a simple way of showing a confidence region for bivariate data on
a plot (a 68% confidence interval is about 1 SD if you just want to
show 1 SD).
On Sat, Mar 3, 2012 at 7:54 AM, drflxms wrote:
> Dear all,
>
> I created a bi
OK, the following seems to work
still do not understand exactly why...
library(MASS)
# parameters:
n<-100
# generate samples:
set.seed(138813)
#seed <- .Random.seed
x<-rnorm(n); y<-rnorm(n)
# estimate non-parameteric density surface via kernel smoothing
den<-kde2d(x, y, n=n)
# store z values of
Dear all,
I created a bivariate normal distribution:
set.seed(138813)
n<-100
x<-rnorm(n); y<-rnorm(n)
and plotted a scatterplot of it:
plot(x,y)
Now I'd like to add the 2D-standard deviation.
I found a thread regarding plotting arbitrary confidence boundaries from
Pascal Hänggi
http://www.mai
On Feb 29, 2012, at 7:08 PM, Leong Keat Chan wrote:
Hi, I would like to make a contour plot using R with the following
information (data at the end): x-axis= arranged according to day
(from 1 to 365, labels= use
I am really getting tired of seeing this message. This must be the
fourth du
Hi, I would like to make a contour plot using R with the following information
(data at the end): x-axis= arranged according to day (from 1 to 365, labels=
use months; up to 365 days in one year), y-axis= depth (labels from 0 at the
top to 7 at the bottom; this is a water depth profile), and z-a
Hi, I would like to make a contour plot using R with the following information
(data at the end): x-axis= arranged according to day (from 1 to 365, labels=
use months; up to 365 days in one year), y-axis= depth (labels from 0 at the
top to 7 at the bottom; this is a water depth profile), and z-a
Hi, I would like to make a contour plot using R with the following information
(data at the end): x-axis= arranged according to day (from 1 to 365, labels=
use months; up to 365 days in one year), y-axis= depth (labels from 0 at the
top to 7 at the bottom; this is a water depth profile), and z-a
Hi, I would like to make a contour plot with the data below, x-axis= Day
(increasing order, day number is out of 365 days of a year), y-axis= Depth
(varies), and z=pH. I tried to use filled.contour function, but not sure the
proper way to ordinate my z results into a matrix with different x and y
l
This is ugly, but I think it works.:
z.2 <- data.frame(data.interp[[3]])
diff_y <- unique(round(diff(data.interp[[2]]), 4))
diff_x <- unique(round(diff(data.interp[[1]]), 4))
total_area <- length(which(z.2!="NA"))*diff_y*diff_x
# percent of total area less than -.5 (as I wanted)
Per_neg_0.5 <- (
Ok,
I've since found this:
# called previously posted dataset "dat"
attach(dat)
library(akima)
data.interp <- interp(x,y,z)
contour(data.interp)
any idea how to calculate area within specified contour lines?
Thanks
chuck.01 wrote
>
> Hello,
> I have some data that will be in the form:
Hello,
I have some data that will be in the form:
structure(list(station = structure(c(20L, 2L, 4L, 19L, 3L, 11L,
1L, 5L, 10L, 12L, 17L, 18L, 6L, 9L, 13L, 16L, 7L, 8L, 15L, 14L
), .Label = c("1", "10", "11", "12", "13", "14", "15", "16",
"17", "18", "19", "2", "3", "4", "5", "6", "7", "8", "9",
help-boun...@r-project.org] On
Behalf Of Andy Richling
Sent: Saturday, January 21, 2012 12:04 PM
To: r-help@r-project.org
Subject: [R] contour(): Thickness contour labels
Hi,
I want to display some contour labels. It works well, but the thickness of
the label is to low. I tried the "labcex
On 01/21/2012 09:38 PM, Roary wrote:
Thanks for your responses Jason and Jim. The ternary plot is definitely the
right style with the triangle fill. However, one of the important features
(that perhaps I understated) is that X3 will have more categories than X1
and X2, therefore the triangular sh
Hi,
I want to display some contour labels. It works well, but the thickness of
the label is to low. I tried the "labcex" command
contour(x,y,z, labcex=2)
But only the size is rising and not the thickness of labels. Only if i set
the value to "labcex=10" the thickness is good, but the size is to
Thanks for your responses Jason and Jim. The ternary plot is definitely the
right style with the triangle fill. However, one of the important features
(that perhaps I understated) is that X3 will have more categories than X1
and X2, therefore the triangular shape is not appropriate. If X1 has I
cat
On 01/20/2012 11:28 PM, Roary wrote:
Hi All,
I have 3 variables which present a perfect linear dependency such that the
third is the sum of the first two. I have an ordinary 2D contour plot on a
square grid with the first two variables forming the axes and the third
naturally being the diagonals
I'm not sure if this is appropriate. If the sum of your variables is
always the same constant, then you might try a Ternary plot (
http://en.wikipedia.org/wiki/Ternary_plot ).
The "vcd" package can make ternary plots.
On 01/20/2012 02:56 PM, Roary wrote:
I have two observed categorical variab
I have two observed categorical variables X1 and X2, with X3=X1+X2, and a
continuous response Y. I can interpolate the surface and construct an
ordinary 2D square contour plot (with X1,X2 axes and X3 on the diagonal).
However, I would like to change the orientation of the plot so that the
axes fit
Not sure if I understand the question: If you have more data the grid
produced by image() or contour() will be finer anyway...
Perhaps we just need an example what you are actually asking for.
Uwe Ligges
On 20.01.2012 13:28, Roary wrote:
Hi All,
I have 3 variables which present a perfect lin
Hi All,
I have 3 variables which present a perfect linear dependency such that the
third is the sum of the first two. I have an ordinary 2D contour plot on a
square grid with the first two variables forming the axes and the third
naturally being the diagonals. From an interpretive point of view it
___
Von: R. Michael Weylandt [michael.weyla...@gmail.com]
Gesendet: Mittwoch, 16. November 2011 18:43
Bis: Sramkova, Anna (IEE)
Cc: r-help@r-project.org
Betreff: Re: [R] Contour on top of 2d histogram
Try the add = TRUE argument to contour.
Michael
On Wed, Nov 16, 2011 at 12:35 PM, Sramkova,
Try the add = TRUE argument to contour.
Michael
On Wed, Nov 16, 2011 at 12:35 PM, Sramkova, Anna (IEE)
wrote:
> Hi all,
>
> I would like to plot one data set as a 2d histogram and another one as a
> contour. I can do it separately with the
> "hist2d" and "contour" functions, but I wonder if the
Hi all,
I would like to plot one data set as a 2d histogram and another one as a
contour. I can do it separately with the
"hist2d" and "contour" functions, but I wonder if there is a way to combine
these two plots into a single one (the ranges of the two plots are the same).
Any suggestions?
T
Hello all,
I'd like to graphically represent an hourly temperature timeseries (
http://r.789695.n4.nabble.com/file/n3215785/data.csv data.csv , and see
below for pre-process of the data) with the R functions image + contour. To
do that I wrote that script :
http://r.789695.n4.nabble.com/file/n32
Hello all,
I'd like to graphically represent an hourly temperature timeseries (
http://r.789695.n4.nabble.com/file/n3179098/data.csv data.csv , and see
below for pre-process of the data) with the R functions image + contour. To
do that I wrote that script (
http://r.789695.n4.nabble.com/file/n317
Dear r users,
I wanted to perform contour figure from response surface model result. I typed
this:
> model = rsm (Index ~ SO(NV, SKLON, pH), bonita)
> summary(model)
> par(mfrow = c(2, 3))
> contour (model, ~NV+SKLON+pH)
However, I got the error answer as follows:
Error in lmobj$data[, nm] :
On Oct 25, 2010, at 3:41 AM, Lorenzo Isella wrote:
On 10/25/2010 01:32 AM, David Winsemius wrote:
You were advised to look at rms. Why have you dismissed this
suggestion?
Using your data setup below and packaging into a dataframe.
require(rms)
ddf <- datadist(xysf <- as.data.frame(xys))
ol
On 10/25/2010 01:32 AM, David Winsemius wrote:
You were advised to look at rms. Why have you dismissed this suggestion?
Using your data setup below and packaging into a dataframe.
require(rms)
ddf <- datadist(xysf <- as.data.frame(xys))
olsfit <- ols(V3~rcs(V1,3)+rcs(V2,3), data=xysf)
bounds <
On 10/25/2010 03:30 AM, Lorenzo Isella wrote:
Hello,
I feel I am drowning in a glass of water.
Consider the following snippet at the end of the email, where I
generated a set of {x,y,s=f(x,y)} values, i.e. a set of 2D coordinates +
a scalar on a circle.
Now, I can get a scatterplot in 3D, but ho
On Oct 24, 2010, at 9:30 AM, Lorenzo Isella wrote:
Hi,
And thanks for helping. I am anyway a bit puzzled, since case (1)
is not
only a matter of interpolation. Probably the point I did not make
clear
(my fault) is that case (1) in my original email does not refer to
an
irregular grid o
Hi,
And thanks for helping. I am anyway a bit puzzled, since case (1) is not
only a matter of interpolation. Probably the point I did not make clear
(my fault) is that case (1) in my original email does not refer to an
irregular grid on a rectangular domain; the set of (x,y) coordinate
could sta
On Oct 24, 2010, at 6:12 AM, Lorenzo Isella wrote:
As to the domain of the function, at least in case (1), that should
arise from the collected data points in (x,y) if the sampling is
dense enough.
And that is precisely what you get from the perimeter function. The
earlier Design packag
On 10/24/2010 02:55 PM, David Winsemius wrote:
On Oct 24, 2010, at 4:30 AM, Lorenzo Isella wrote:
Dear All,
I would like to plot a scalar (e.g. a temperature) on a
non-rectangular domain (or even better: I would simply like to be able
to draw a contour plot on an arbitrary 2D domain). I wonder
On Oct 24, 2010, at 4:30 AM, Lorenzo Isella wrote:
Dear All,
I would like to plot a scalar (e.g. a temperature) on a non-
rectangular domain (or even better: I would simply like to be able
to draw a contour plot on an arbitrary 2D domain). I wonder if there
is any tool to achieve that with
On 24.10.2010 14:14, Lorenzo Isella wrote:
On 10/24/2010 01:51 PM, (Ted Harding) wrote:
On 24-Oct-10 11:30:57, Lorenzo Isella wrote:
Dear All,
I would like to plot a scalar (e.g. a temperature) on a non-rectangular
domain (or even better: I would simply like to be able to draw a
contour plot
On 10/24/2010 01:51 PM, (Ted Harding) wrote:
On 24-Oct-10 11:30:57, Lorenzo Isella wrote:
Dear All,
I would like to plot a scalar (e.g. a temperature) on a non-rectangular
domain (or even better: I would simply like to be able to draw a
contour plot on an arbitrary 2D domain). I wonder if there
On 24-Oct-10 11:30:57, Lorenzo Isella wrote:
> Dear All,
> I would like to plot a scalar (e.g. a temperature) on a non-rectangular
> domain (or even better: I would simply like to be able to draw a
> contour plot on an arbitrary 2D domain). I wonder if there is any
> tool to achieve that with R. I
Dear All,
I would like to plot a scalar (e.g. a temperature) on a non-rectangular
domain (or even better: I would simply like to be able to draw a contour
plot on an arbitrary 2D domain). I wonder if there is any tool to
achieve that with R. I did some online search in particular on the list
a
If Dennis' interpretation of your request is correct then Harrell rms/
Hmisc packages provide a mechanism for restricting plotting of
contours to the region within a perimeter. He has a perimeter function
and the bplot function takes a perim argument. The reason I did not
offer it earlier is
Hi:
Check out this post on R-help from February, and look carefully at the
solution of Walmes Zeviani - I believe it's close to what you're requesting:
http://r.789695.n4.nabble.com/Triangular-filled-contour-plot-td1557386.html
HTH,
Dennis
On Fri, Oct 22, 2010 at 6:15 PM, Yunting Sun wrote:
>
Hello,
anyone knows if there is a way in R to draw contour on a simplex based on a
function f(x,y,z) with domain (x+y+z = 1)?
Thank you!
gigi
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https://stat.ethz.ch/mail
Hi All
I have been trying to plot irregular XYZ data on world / country map, where X
and Y are llongitude and latitude coordinates and Z is a variable. My problem
is I get contour lines over water bodies. The method I follow is:>
library(akima)> library(maps)> library(mapdata)> library(gpclib)>
On 15/09/2010 11:13 AM, Tonja Krueger wrote:
Hi all,
I used contour() to add contour lines to a plot. Now I’m wondering if there is
a way to get an output of the calculated x- and y- coordinates of the contour
lines?
?contourLines
Duncan Murdoch
___
On Sep 15, 2010, at 11:13 AM, Tonja Krueger wrote:
Hi all,
I used contour() to add contour lines to a plot. Now I’m wondering
if there is a way to get an output of the calculated x- and y-
coordinates of the contour lines?
?contourLines # as was suggested to be the first "See(n) Also"
Hi all,
I used contour() to add contour lines to a plot. Now I’m wondering if there is
a way to get an output of the calculated x- and y- coordinates of the contour
lines?
Tonja
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On 29-Jun-10 08:53:48, Kirkeby wrote:
> Hi again.
>
> I have made an example of my data:
>
> x<-c(1,2,3,4,1,2,3,4,1,2,3,4,1,2,3,4)
> y<-c(1,1,1,1,2,2,2,2,3,3,3,3,4,4,4,4)
> z <- c(12,23,23,42,12,1,1,32,5,45,65,76,32,21,23,43)
> data <- unique(cbind(x,y,z))
> contour(x,y,z, col="red", xlim=c(0,1)
Hi again.
I have made an example of my data:
x<-c(1,2,3,4,1,2,3,4,1,2,3,4,1,2,3,4)
y<-c(1,1,1,1,2,2,2,2,3,3,3,3,4,4,4,4)
z <- c(12,23,23,42,12,1,1,32,5,45,65,76,32,21,23,43)
data <- unique(cbind(x,y,z))
contour(x,y,z, col="red", xlim=c(0,1), ylim=c(0,1), labcex=0.7, cex="12")
-which gives an e
Hello everyone.
I have been dealing with this for a while. I have built a spatial prediction
model for densities of mosquitoes on a field, based om empirical data. I
need to plot the field area with the predicted densities in a heatmap,
contour or likewise, and compare it visually with i.e. a loe
On 22/06/2010 9:29 AM, dbeest wrote:
Hi All,
I'm having difficulty making a contour plot a would like some help.
A standard contourplot can be made by having an x,y, and some matrix (shape
x*y) with contents:
x = 1:10
y = 1:10
cont <- matrix(runif(100,min=1,max=2),nrow=10,ncol=10)
filled.conto
Hi All,
I'm having difficulty making a contour plot a would like some help.
A standard contourplot can be made by having an x,y, and some matrix (shape
x*y) with contents:
x = 1:10
y = 1:10
cont <- matrix(runif(100,min=1,max=2),nrow=10,ncol=10)
filled.contour(x,y,cont)
Looks very nice.
Somet
Further to Uwe's answer: I suspect that you're not telling us
the whole story (that's why it's so useful to have reproducible
code).
Try this:
x <- y <- 1:3
z <- outer(x, y)
z[1,1] <- 1/0
persp(x,y,z)
which results in:
Error in persp.default(x, y, z) : invalid 'z' limits
So, are some your
On 07.02.2010 22:46, Andrew Wang wrote:
I have this data set that both x& y are ordered vectors of length 600& 700
respectively; z is a 600 by 700 matrix whose entry z[i,j] is either a missing value
(indicated by 'NaN') or a real number between 0 and 1. The contour function
contour(x,y,z
I have this data set that both x & y are ordered vectors of length 600 & 700
respectively; z is a 600 by 700 matrix whose entry z[i,j] is either a missing
value (indicated by 'NaN') or a real number between 0 and 1. The contour
function
contour(x,y,z)
gives me a blank picture. I guess the
karine heerah wrote:
Hi everybody,
I am using the contour function to draw isobares. And i would like to to bold
contours for an interval of 500m and weak contour for an interval of 100m.
Can someone help me with this?
Thanks a lot
Karine
___
Hi everybody,
I am using the contour function to draw isobares. And i would like to to bold
contours for an interval of 500m and weak contour for an interval of 100m.
Can someone help me with this?
Thanks a lot
Karine
_
On Nov 22, 2009, at 8:01 PM, Duncan Murdoch wrote:
On 22/11/2009 6:28 PM, (Ted Harding) wrote:
Wow! (Top-posting for once, since there's no natural other place ...)
Thanks Peter, David and Duuncan for the suggestions. I'll look at the
later ones from David & Duncan later (it's getting late her
On 22/11/2009 6:28 PM, (Ted Harding) wrote:
Wow! (Top-posting for once, since there's no natural other place ...)
Thanks Peter, David and Duuncan for the suggestions. I'll look at the
later ones from David & Duncan later (it's getting late here).
However, as something to work on if you want to,
Wow! (Top-posting for once, since there's no natural other place ...)
Thanks Peter, David and Duuncan for the suggestions. I'll look at the
later ones from David & Duncan later (it's getting late here).
However, as something to work on if you want to, here is a toy
example, based on the same overa
On Nov 22, 2009, at 5:35 PM, Duncan Murdoch wrote:
On 22/11/2009 5:21 PM, David Winsemius wrote:
On Nov 22, 2009, at 4:57 PM, Peter Ehlers wrote:
Hi Ted,
This won't solve your problem, but a small improvement might
be to place the labels over the lines rather than the other
way around. It wi
On 22/11/2009 5:35 PM, Duncan Murdoch wrote:
On 22/11/2009 5:21 PM, David Winsemius wrote:
On Nov 22, 2009, at 4:57 PM, Peter Ehlers wrote:
Hi Ted,
This won't solve your problem, but a small improvement might
be to place the labels over the lines rather than the other
way around. It will defi
On 22/11/2009 5:21 PM, David Winsemius wrote:
On Nov 22, 2009, at 4:57 PM, Peter Ehlers wrote:
Hi Ted,
This won't solve your problem, but a small improvement might
be to place the labels over the lines rather than the other
way around. It will definitely avoid putting red lines over
black ones
On Nov 22, 2009, at 4:57 PM, Peter Ehlers wrote:
Hi Ted,
This won't solve your problem, but a small improvement might
be to place the labels over the lines rather than the other
way around. It will definitely avoid putting red lines over
black ones:
x <- -6:16
z <- outer(x,x)
contour(z, label
Hi Ted,
This won't solve your problem, but a small improvement might
be to place the labels over the lines rather than the other
way around. It will definitely avoid putting red lines over
black ones:
x <- -6:16
z <- outer(x,x)
contour(z, labels="", col=2)
contour(z, lty=0, labcex=1, add=TRUE)
Greetings, All!
I want to draw contour lines in red, using contour(), but also
have the contour labels (for the level-values) in black so that
they will stand out against a coloured background already generated
using filled.contour() (the background shades from green at low
levels of "risk" to red
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