Thanks william,
I got it now...
Elisa
From: wdun...@tibco.com
To: eliza_bo...@hotmail.com; ruipbarra...@sapo.pt
CC: r-help@r-project.org
Subject: RE: [R] Continuous columns of matrix
Date: Sat, 25 May 2013 02:33:40 +
What you call "continuous" I call "cyclic" (wi
use apply() if you to want to run it over each column.
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
From: eliza botto [mailto:eliza_bo...@hotmail.com]
Sent: Friday, May 24, 2013 4:41 PM
To: ruipbarra...@sapo.pt; William Dunlap
Cc: r-help@r-project.org
Subject: RE: [R] Continuous columns o
Bingo!!!
This time it worked
Thanks arun
Thankyou very much indeed..
:D
Elisa
> Date: Fri, 24 May 2013 17:03:33 -0700
> From: smartpink...@yahoo.com
> Subject: Re: [R] Continuous columns of matrix
> To: eliza_bo...@hotmail.com
> CC: wdun...@tibco.com; r-help@r-project.org
33451964, 1.49415144965002, 1.30559703478921
> >)
> >> f(x, plot=TRUE) # the plot illustrates what it is doing
> >IndexValue
> > 1 5 1.463772
> > 211 1.494151
> >
> > Bill Dunlap
> > Spotfire, TIBCO Software
> > wdunlap
1.49415144965002, 1.30559703478921
> >)
> >> f(x, plot=TRUE) # the plot illustrates what it is doing
> >IndexValue
> > 1 5 1.463772
> > 211 1.494151
> >
> > Bill Dunlap
> > Spotfire, TIBCO Software
> > wdunlap tibco.com
> >
&
the following
[,1] [,2]
index 5.00 11.00
values 1.463772 1.494151
Is there anyway of doing it??
Thanks in advance
Elisa
Date: Fri, 24 May 2013 17:02:56 +0100
From: ruipbarra...@sapo.pt
To: eliza_bo...@hotmail.com
CC: b...@xs4all.nl; r-help@r-project.org
Subject: Re: [R] Continuous
t;
> > -Original Message-
> > From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> > Behalf
> > Of eliza botto
> > Sent: Friday, May 24, 2013 2:10 PM
> > To: ruipbarra...@sapo.pt; r-help@r-project.org
> > Subject: Re: [R] Con
CO Software
wdunlap tibco.com
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> Behalf
> Of eliza botto
> Sent: Friday, May 24, 2013 2:10 PM
> To: ruipbarra...@sapo.pt; r-help@r-project.org
> Subject: Re: [R] Continuous colu
es 1.463772 1.494151
Is there anyway of doing it??
Thanks in advance
Elisa
> Date: Fri, 24 May 2013 17:02:56 +0100
> From: ruipbarra...@sapo.pt
> To: eliza_bo...@hotmail.com
> CC: b...@xs4all.nl; r-help@r-project.org
> Subject: Re: [R] Continuous columns of matrix
>
> Hello
Thankyou very very much arun.:Delisa
> Date: Fri, 24 May 2013 11:08:56 -0700
> From: smartpink...@yahoo.com
> Subject: Re: [R] Continuous columns of matrix
> To: eliza_bo...@hotmail.com
> CC: r-help@r-project.org; ruipbarra...@sapo.pt
>
> Hi,
> You may also try:
>
do.call(rbind,fun2(x))) #Rui's function
identical(lst1,lst2)
#[1] TRUE
A.K.
- Original Message -
From: eliza botto
To: Berend Hasselman
Cc: "r-help@r-project.org"
Sent: Friday, May 24, 2013 6:41 AM
Subject: Re: [R] Continuous columns of matrix
There you go!!!
structure(c(
Thanks rui..That was all i wanted...
Elisa
> Date: Fri, 24 May 2013 17:02:56 +0100
> From: ruipbarra...@sapo.pt
> To: eliza_bo...@hotmail.com
> CC: b...@xs4all.nl; r-help@r-project.org
> Subject: Re: [R] Continuous columns of matrix
>
> Hello,
>
> No problem. Just
za_bo...@hotmail.com
CC: b...@xs4all.nl; r-help@r-project.org
Subject: Re: [R] Continuous columns of matrix
Hello,
Something like this?
fun2 <- function(x){
n <- length(x)
imx <- which.max(x)
if(imx == 1){
x[2] <- x[n] <- Inf
}e
pbarra...@sapo.pt
> To: eliza_bo...@hotmail.com
> CC: b...@xs4all.nl; r-help@r-project.org
> Subject: Re: [R] Continuous columns of matrix
>
> Hello,
>
> Something like this?
>
>
> fun2 <- function(x){
> n <- length(x)
> imx <- which.max(x)
>
umber 12 than the second maximum can be in any
row other than 1 and 11...thankyou very much for your help
elisa
Date: Fri, 24 May 2013 12:37:37 +0100
From: ruipbarra...@sapo.pt
To: eliza_bo...@hotmail.com
CC: b...@xs4all.nl; r-help@r-project.org
Subject: Re: [R] Continuous columns of matrix
He
nl; r-help@r-project.org
> Subject: Re: [R] Continuous columns of matrix
>
> Hello,
>
> Berend is right, it's at least confusing. To get just the index of the
> maximum value in each column,
>
> apply(mat, 2, which.max)
>
>
> To get that index and the two neighbours
1.19319875840883,
0.533232612926756, 0.225531074123974, 0.122949089115578), .Dim = c(12L, 6L))
Thanks once again..
Elisa
Subject: Re: [R] Continuous columns of matrix
From: b...@xs4all.nl
Date: Fri, 24 May 2013 12:36:47 +0200
CC: r-help@r-project.org
To: eliza_bo...@hotmail.com
On 24-05-2013, at 12:24, eliz
, 0.0926010253161898, 0.362209761457517, 1.45769283057202,
3.16165004659667, 2.74903557756267, 1.94633472878995, 1.19319875840883,
0.533232612926756, 0.225531074123974, 0.122949089115578), .Dim = c(12L, 6L))
Thanks once again..
Elisa
> Subject: Re: [R] Continuous columns of matrix
> F
On 24-05-2013, at 12:24, eliza botto wrote:
> Dear useRs,If i have a matrix, say, 12 rows and 6 columns. The columns are
> continuous. I want to find the index of maximum values and the actual
> maximum values. The maximum values in each column are the highest values and
> the values greater
Dear useRs,If i have a matrix, say, 12 rows and 6 columns. The columns are
continuous. I want to find the index of maximum values and the actual maximum
values. The maximum values in each column are the highest values and the values
greater than or equal to 80% of the maximum value. Moreover, i
20 matches
Mail list logo
