Re: [R] Comparison of the amount of computation

Dear Pert, Many thanks to your reply. Fully you are right! Best wishes, Helin. -- View this message in context: http://r.789695.n4.nabble.com/Comparison-of-the-amount-of-computation-tp3448436p3449722.html Sent from the R help mailing list archive at Nabble.com. ___

Re: [R] Comparison of the amount of computation

On Thu, Apr 14, 2011 at 12:40:53AM -0700, helin_susam wrote: > Hi Petr, > > Your idea looks like logically. So, can we say this with your idea; the > expected number of computation in unique(sample(...)) is fewer than > sample(...). Because, the expected length is 63.39677 in unique case, while >

Re: [R] Comparison of the amount of computation

Hi Petr, Your idea looks like logically. So, can we say this with your idea; the expected number of computation in unique(sample(...)) is fewer than sample(...). Because, the expected length is 63.39677 in unique case, while the expected length is 100 in non-unique case ? Thanks for reply, Helin

Re: [R] Comparison of the amount of computation

On Wed, Apr 13, 2011 at 04:12:39PM -0700, helin_susam wrote: > Hi dear list, > > I want to compare the amount of computation of two functions. For example, > by using this algorithm; > > data <- rnorm(n=100, mean=10, sd=3) > > output1 <- list () > for(i in 1:100) { > data1 <- sample(100, 100, re

[R] Comparison of the amount of computation

Hi dear list, I want to compare the amount of computation of two functions. For example, by using this algorithm; data <- rnorm(n=100, mean=10, sd=3) output1 <- list () for(i in 1:100) { data1 <- sample(100, 100, replace = TRUE) statistic1 <- mean(data1) output1 <- c(output1, list(statistic1)) }