Thanks. It works!
I think I found another solution, working straight with the indicator
matrix.
> count <- factor(table(apply(ind, 1, paste, collapse="")))
However, that way I can't store the indices of the collapsed rows.
-Angelos Markos
__
R-help@r
On Mon, May 12, 2008 at 11:27 AM, amarkos <[EMAIL PROTECTED]> wrote:
> Thanks, it works!
> Could you please provide the direct method you mentioned for the
> multivariate case?
I'm not sure what you mean. I looked at what I wrote and I don't see
anything that would fit that description.
May I s
On Sun, May 11, 2008 at 9:49 AM, amarkos <[EMAIL PROTECTED]> wrote:
> On May 11, 4:47 pm, "Douglas Bates" <[EMAIL PROTECTED]> wrote:
>
>> Do you mean that you want to collapse similar rows into a single row
>> and perhaps a count of the number of times that this row occurs?
>
> Let me rephrase the
On May 11, 4:47 pm, "Douglas Bates" <[EMAIL PROTECTED]> wrote:
> Do you mean that you want to collapse similar rows into a single row
> and perhaps a count of the number of times that this row occurs?
Let me rephrase the problem by providing an example.
Input:
A =
[,1] [,2]
[1,]1
On Sat, May 10, 2008 at 5:27 AM, amarkos <[EMAIL PROTECTED]> wrote:
> An indicator matrix is a binary matrix with orthogonal columns whose
> rows sum to 1. A row of this matrix could be [0 1 0 0]. My problem is
> to group the similar rows (profiles) so that to create a compact form
> of the matrix.
An indicator matrix is a binary matrix with orthogonal columns whose
rows sum to 1. A row of this matrix could be [0 1 0 0]. My problem is
to group the similar rows (profiles) so that to create a compact form
of the matrix.
Is there an R function that deals with this problem or do I have to
write
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