Add the drop = TRUE command to split
?split
split(a, cut(a$spending, breaks = (0:5)*100), drop = TRUE)
Michael
On Mon, Dec 5, 2011 at 4:06 PM, Diviya Smith wrote:
> Thank you very much Michael. This is very helpful. However, if there is any
> way to exclude zero length bins. Lets imagine that t
Thank you very much Michael. This is very helpful. However, if there is any
way to exclude zero length bins. Lets imagine that the matrix was as
follows -
a <- data.frame(patient=1:7, charges=c(100,500,200,90,400,500,600),
age=c(0,3,5,7,10,16,19), spending=c(10, 60, 110, 200, 400, 450, 500))
bi
Just a clarification: I can't get round to work as I first expected so
if you want to do bins by 100's you'd probably want:
split(a, cut(a$spending, breaks = (0:5)*100))
Michael
On Mon, Dec 5, 2011 at 3:41 PM, R. Michael Weylandt
wrote:
> I'd so something like
>
> split(a, a$spending)
>
> and y
I'd so something like
split(a, a$spending)
and you can include a round(a$spending, -2) or something similar if
you want to group by the 100's.
Michael
On Mon, Dec 5, 2011 at 3:37 PM, Diviya Smith wrote:
> Hello there,
>
> I have a matrix with some data and I want to split this matrix based on
Hello there,
I have a matrix with some data and I want to split this matrix based on the
values in one column. Is there a quick way of doing this? I have looked at
cut but I am not sure how to exactly use it?
for example:
I would like to split the matrix "a" based on the spending such that the
da
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