Rui-
Just a quick question. I understand your comment on using ANOVA, but
doesn't this only test for similarities of the mean. We are trying to see if
a the same model can fit for two or three months, therefore have the similar
slope and intercept. The ANOVA would only do one part of this correct
Hello,
I'm glad it helped.
As for your second question, I don't know, but I'm not very comfortable with
the way you're doing things.
Why subtract the coefficients of model 1 from model 2?
And why the dummy? Why set model 1 to zero?
Isn't it better to use anova's F? After all, it's designed for i
Rui-
Thanks this definitely helps, just one quick question. How would you code
the values of chi-fm and chi-fms to change based on the degrees of freedom
of each model H(i)?
Meredith
Rui Barradas wrote
>
> Hello,
>
> Yes, it does help. Now we can see your data and what you're doing.
> What f
Hello,
Yes, it does help. Now we can see your data and what you're doing.
What follows is a suggestion on what you could do, not full solution.
(You forgot to say what X1 is, but I don't think it's important to
understand the suggestion.)
(If I'm wrong, say something.)
milwaukeephos <- read.csv(
dput: http://r.789695.n4.nabble.com/file/n4620188/milwaukeephos.csv
milwaukeephos.csv
# Feb-march
> modelH_febmarch<-lm(llfeb_march~lffeb_march)
>modelHa_febmarch<-lm(llfeb_march~X1feb_mar+lffeb_march)
> anova(modelHa_febmarch)
> coefficients(modelH_febmarch)
(Intercept) lffeb_march
-2.429890
Hello,
I'm not at all sure if I understand your problem. Does this describe it?
test first model for months 1 and 2
if test statistic less than critical value{
test second model for months 1 and 2
print results of the first and second tests? just one of them?
}
move on to months
R Users-
I have been trying to automate a manual code that I have developed for
calling in a .csv file, isolating certain rows and columns that correspond
to specified months:
something to the effect
i=name.csv
N=length(i$month)
iphos1=0
iphos2=0
isphos3=0
for i=1,N
if month=1
iphos1=iphos+1
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