On Jun 9, 2012, at 1:02 PM, Onur Uncu wrote:
Thank you Michael. One follow up question: In the solution using
apply(), why are we feeding x[2] inside testfun instead of x[[2]]?
Aren't we supposed to feed the vector of values to the function, which
is achieved by x[[2]]?
`apply` sends the colu
Thank you Michael. One follow up question: In the solution using
apply(), why are we feeding x[2] inside testfun instead of x[[2]]?
Aren't we supposed to feed the vector of values to the function, which
is achieved by x[[2]]?
Thnks.
On Sat, Jun 9, 2012 at 3:38 PM, R. Michael Weylandt
wrote:
> N
No worries -- it's an important question and it introduces you to one
of the most important R idioms. [And you get bonus points for having a
well formed question!]
You're probably looking for something like this:
apply(testframe, 1, function(x) testfun(x[2]))
Which goes row-by-row and substitute
Apologees the novice question. Currently climbing up the learning curve of R.
Suppose I have the following function and the data.frame:
testfun<-function(x=1,y=2) x+y
testframe=data.frame(col1=c(1,2),col2=c(3,4))
When evaluating testfun, I want to use the default value for y (which
is 2) and fo
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