If one puts the gc() call prior to the expressions themselves, one
gets consistently ... different results:
library("rbenchmark")
v<-rep(1:500,1:500); x<-5; benchmark(
which= c(gc(),length(which(x==v))), index= c(gc(),
length(v[v==x])), sum= c(gc(), sum(v==x)),
replications=200,
Answering my own question: if I explicitly garbage collecte before the
benchmark then 'index' always wins, which probably also answers the
original question.
v<-rep(1:1000,1:1000); x<-5; gc(); benchmark(replications=200,
columns=c("test","elapsed"), order="elapsed", which=length(which(x==v)),
When trying out a couple of different approaches to this problem I get
rather different answers between runs. Anybody know why?
> library("rbenchmark")
> v<-rep(1:1000,1:1000); x<-5; benchmark(replications=200,
columns=c("test","elapsed"), order="elapsed", which=length(which(x==v)),
index=len
Hi,
I have a vector "v" and would like to find the number of occurrence of
element "x" in the same.
Is there a way other than,
sum(as.integer(v==x)) or length(which(x==v))
to do the this.
I have a huge file to process and do this. Both the above described methods
are pretty slow w
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