Re: [R] About scan

2010-08-17 Thread Joshua Wiley
On Tue, Aug 17, 2010 at 9:20 PM, Stephen Liu wrote: > - Original Message > > From: Joshua Wiley > To: Stephen Liu > Cc: r-help@r-project.org > Sent: Wed, August 18, 2010 12:10:51 PM > Subject: Re: [R] About scan > > Hi Josh, > > Thanks for your adv

Re: [R] About scan

2010-08-17 Thread Stephen Liu
- Original Message From: Joshua Wiley To: Stephen Liu Cc: r-help@r-project.org Sent: Wed, August 18, 2010 12:10:51 PM Subject: Re: [R] About scan Hi Josh, Thanks for your advice. - snip - >> x <- scan() >1: 1 2 3 4 5 >6: I tried it before. It'll continue ask

Re: [R] About scan

2010-08-17 Thread Joshua Wiley
Hi Stephen, Maybe it is just me, but I am not clear what your question is. scan() is a function with a variety of arguments. When these are not explicitly named, they go in order. So, scan(1, 2, 3, 4, 5) is equivalent to scan(file = 1, what = 2, nmax = 3, n = 4, sep = 5), which is clearly nonse

[R] About scan

2010-08-17 Thread Stephen Liu
Hi folks, I followed an online example to input data; > x = scan(1,2,3,4,5) Error in scan(1, 2, 3, 4, 5) : either specify 'nmax' or 'n', but not both. It can't work. > x = c(1,2,3,4,5) > x [1] 1 2 3 4 5 It works. Whether "scan" is replaced with "c" ? > ?c . Usage: c(..., recur