You need to read in the line with read.table to parse the string. The
solution assumes a dataframe .
Sent from my iPhone
On Aug 5, 2008, at 7:16, "Henrique Dallazuanna" <[EMAIL PROTECTED]>
wrote:
I think that you need:
p <- scan(textConnection(p), what = "")
On Tue, Aug 5, 2008 at 7:41
I think that you need:
p <- scan(textConnection(p), what = "")
On Tue, Aug 5, 2008 at 7:41 AM, Gundala Viswanath <[EMAIL PROTECTED]> wrote:
> Thanks Jim,
>
> But how can I modify this line of yours
>
> y <- lapply(split(x, x$V3), "[[", 8)
>
> to suit my 'comp.ll'
>
> I tried this but fail:
>> p
Thanks Jim,
But how can I modify this line of yours
y <- lapply(split(x, x$V3), "[[", 8)
to suit my 'comp.ll'
I tried this but fail:
> p <- "\tGene 11340 211952_at RANBP5 k= 1 LL= -970.692 "
> y <- lapply(split(p, p[3]), "[[", 8)
> y
> list()
- Gundala Viswanath
Jakarta - Indonesia
O
Does this get you close to what you want:
> x <- read.table(textConnection("Gene 11340 211952_at RANBP5 k= 1 LL=
> -970.692
+ Gene 11340 211952_at RANBP5 k= 2 LL= -965.35
+ Gene 11340 211952_at RANBP5 k= 3 LL= -963.669
+ Gene 12682 213301_x_at TRIM24 k= 1 LL= -948.527
+ Gene 12682 21
Hi all,
I have the following data in which I want to parse and
store them in a list
__DATA__
> print(comp.ll)
[1] "\tGene 11340 211952_at RANBP5 k= 1 LL= -970.692 "
[2] "\tGene 11340 211952_at RANBP5 k= 2 LL= -965.35 "
[3] "\tGene 11340 211952_at RANBP5 k= 3 LL= -963.669 "
[4
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