On Thu, 28-Jun-2012 at 06:27PM +1200, Patrick Connolly wrote:
|> On Tue, 26-Jun-2012 at 11:57PM -0500, Erin Hodgess wrote:
|>
|> |> Hello again:
|> |>
|> |> Here is a solution to the dates without leading zeros:
|> |>
[...]
|>
|> |> This is not particularly elegant, but it does the trick.
|>
On Tue, 26-Jun-2012 at 11:57PM -0500, Erin Hodgess wrote:
|> Hello again:
|>
|> Here is a solution to the dates without leading zeros:
|>
|> pou1 <- function(x) {
|> #Note: x is a data frame
|> #Assume that Column 1 has the date
|> #Column 2 has station
|> #Column 3 has min
Please don't change subject lines for follow-on comments. It messes up
threading in most readers: e.g.,
https://stat.ethz.ch/pipermail/r-help/2012-June/thread.html
Michael
On Tue, Jun 26, 2012 at 11:57 PM, Erin Hodgess wrote:
> Hello again:
>
> Here is a solution to the dates without leading ze
Hello again:
Here is a solution to the dates without leading zeros:
pou1 <- function(x) {
#Note: x is a data frame
#Assume that Column 1 has the date
#Column 2 has station
#Column 3 has min
#Column 4 has max
library(stringr)
w <- character(length=nrow(x))
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