Re: [R] A simple string alienation problem

2020-04-15 Thread Richard O'Keefe
I'm very confused by the phrase "string alienation". You mention two problems: (1) remove " from a string sub('"', '', vector.of.strings) will do that. See ?grep for details. (2) split a string at occurrences of / strsplit(vector.of.strings, "/") will do that.

Re: [R] A simple string alienation problem

2020-04-14 Thread PIKAL Petr
ssage- > From: R-help On Behalf Of Soumyadip > Bhattacharyya > Sent: Tuesday, April 14, 2020 12:55 PM > To: r-help-requ...@r-project.org; r-help-ow...@r-project.org; r-help@r- > project.org; ericjber...@gmail.com > Subject: [R] A simple string alienation problem > > ***Dear

[R] A simple string alienation problem

2020-04-14 Thread Soumyadip Bhattacharyya
***Dear Eric,* sending from gmail following the way you suggested. Hope now everyone can see this email. I have also attached the first 50 rows of the FIght.csv.*** ***Output - I will try to do Market basket analysis on this to find out rules that I am learning. so once I have the data in

Re: [R] A simple string alienation problem

2020-04-14 Thread Eric Berger
Hi Sam, My code below adds new columns to your data frame so you have the original columns in order to compare. (Also this could help in case there are a few rows that don't work in the full set.) > x <- read.csv("Fight.csv", stringsAsFactors = F, header = F) > x$V3 <- sub("\\\"","",x$V1) # remo