[R] 1: Setting LC_CTYPE failed, using "C"

At startup or and using R CMD .. I stumble about 1: Setting LC_CTYPE failed, using "C" 2: Setting LC_TIME failed, using "C" 3: Setting LC_MESSAGES failed, using "C" 4: Setting LC_MONETARY failed, using "C" Iam am working with R version 3.3.2 (2016-10-31) Platform: x86_64-apple-darwin13.4.0 (64-

[R] 1. What function to use to read all the files in a directory to a vector in R code? 2. What function to use to coerce character string into numeric?

Le 10/11/2014 22:15, John McKown a écrit : On Mon, Nov 10, 2014 at 7:12 AM, Aditya Singh wrote: Hi, I have 2 queries: 1. What function to use to read all the files in a directory to a vector in R code? In the package phenology, a function read_folder can be used to read all the files at one

Re: [R] 1. What function to use to read all the files in a directory to a vector in R code? 2. What function to use to coerce character string into numeric?

On Mon, Nov 10, 2014 at 4:15 PM, John McKown wrote: > On Mon, Nov 10, 2014 at 7:12 AM, Aditya Singh wrote: [snip] > Suggestion 2: If you haven't already, I would strongly recommend getting & > installing RStudio. It is free (as in beer, which is a curious phrase > because beer isn't usually fre

Re: [R] 1. What function to use to read all the files in a directory to a vector in R code? 2. What function to use to coerce character string into numeric?

On Mon, Nov 10, 2014 at 7:12 AM, Aditya Singh wrote: > Hi, > I have 2 queries: > 1. What function to use to read all the files in a directory to a vector > in R code? > 2. What function to use to coerce character string into numeric? > As a help to others, I figured out to use setwd("C:/") to

Re: [R] 1. What function to use to read all the files in a directory to a vector in R code? 2. What function to use to coerce character string into numeric?

1. There is no built-in function to do that, but it can be done if you learn the basics of R [1]. For one thing, there is no assurance that all files in a directory will fit into vectors.. Most data fit better into data frames, and some data like XML need to be stored in lists of lists. So your

[R] 1. What function to use to read all the files in a directory to a vector in R code? 2. What function to use to coerce character string into numeric?

Hi, I have 2 queries: 1. What function to use to read all the files in a directory to a vector in R code? 2. What function to use to coerce character string into numeric? As a help to others, I figured out to use setwd("C:/") to set working directory! Aditya [[alternative HTML version

Re: [R] 1-dinemsional point process

It's unclear why density estimates are not being mentioned. Also suggest you search: install.packages("sos") require(sos) findFn("scan statistic") On Jun 30, 2014, at 7:35 PM, Doobs wrote: > Hi, > As a new user, is it possible to look at clustering/dispersion processes of > a 1D point process

[R] 1-dinemsional point process

Hi, As a new user, is it possible to look at clustering/dispersion processes of a 1D point process (i.e. points along a transect)? My limited understanding is that spatstat is for 2&3D point patterns. Thanks -- View this message in context: http://r.789695.n4.nabble.com/1-dinemsional-point-pr

Re: [R] (1 - 0.7) == 0.3

HI, 2-0.7==0.3 #[1] FALSE ##May be u meant  2-0.7==1.3 #[1] TRUE Possibly R FAQ 7.31 Also, check http://rwiki.sciviews.org/doku.php?id=misc:r_accuracy all.equal(2-0.7,1.3) #[1] TRUE  all.equal(1-0.7,0.3) #[1] TRUE (1-0.7)<(0.3+.Machine$double.eps^0.5) #[1] TRUE  p <- c(0.2, 0.4, 0.6, 0.8, 1)

Re: [R] 1-KM and Cumulative incidence

On 11/12/2012 06:50 AM, cachimo wrote: Dear I want to know how to plot "1-KM" and "Cumulative incidence" curves in on graph. Thanks For 1-KM, see the fun argument to plot.survfit. Do you mean the Cumulative incidence curve for competing risks? If so, see the cmprsk package for one approa

[R] 1-KM and Cumulative incidence

Dear I want to know how to plot "1-KM" and "Cumulative incidence" curves in on graph. Thanks -- View this message in context: http://r.789695.n4.nabble.com/1-KM-and-Cumulative-incidence-tp4649301.html Sent from the R help mailing list archive at Nabble.com. __

Re: [R] (1-1e-100)==1 true?

On Mon, Jun 18, 2012 at 02:26:41PM -0700, whf1984911 wrote: > Hi, > > This problems has bothered me for the lase couple of hours. > > > 1e-100==0 > [1] FALSE > > (1-1e-100)==1 > [1] TRUE > > How can I tell R that 1-1e-100 does not equal to 1, actually, I found out > that > > (1-1e-16)==1 >

Re: [R] (1-1e-100)==1 true?

On 18-Jun-2012 21:26:41 whf1984911 wrote: > Hi, > > This problems has bothered me for the lase couple of hours. > >> 1e-100==0 > [1] FALSE >> (1-1e-100)==1 > [1] TRUE > > How can I tell R that 1-1e-100 does not equal to 1, actually, > I found out that > > (1-1e-16)==1 > [1] FALSE >> (1-1e-1

Re: [R] (1-1e-100)==1 true?

This is standard behaviour for a floating-point computational system like R. You might like to take a look at this blog post for a backgrounder on floating-point arithmetic in R. http://blog.revolutionanalytics.com/2009/03/when-is-a-zero-not-a-zero.html # David Smith On Mon, Jun 18, 2012 at 2:26

[R] (1-1e-100)==1 true?

Hi, This problems has bothered me for the lase couple of hours. > 1e-100==0 [1] FALSE > (1-1e-100)==1 [1] TRUE How can I tell R that 1-1e-100 does not equal to 1, actually, I found out that > (1-1e-16)==1 [1] FALSE > (1-1e-17)==1 [1] TRUE The reason I care about this is that I was try to u

Re: [R] 1 not equal to 1, and rep command

> -Original Message- > From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] > On Behalf Of Benjamin Høyer > Sent: Monday, September 12, 2011 6:19 AM > To: r-help@r-project.org > Cc: t...@novozymes.com > Subject: [R] 1 not equal to 1, and rep c

Re: [R] 1 not equal to 1, and rep command

Not so strange, in fact this is FAQ 7.31, and has to do (as you guess) with the way that computers store numbers. You need to do as you did, and use round() or floor() or similar to ensure that you get the results you expect. Sarah 2011/9/12 Benjamin Høyer : > Hi > > I need to use rep() to get a

[R] 1 not equal to 1, and rep command

Hi I need to use rep() to get a vector out, but I have spotted something very strange. See the reproducible example below. N <- 79 seg <- 5 segN <- N / seg # = 15.8 d1 <- seg - ( segN - floor(segN) ) * seg d1# = 1 rep(2, d1) # = numeric(0), strange - why doesn't

Re: [R] 1 continuous non-normal variable ~ 4 factors + 1 continuous covariate (with interactions)

Thanks, I guess I can do that, and it actually seem appropriate for one of my variable. But can you do post-hoc tests on a survival analysis? Use contrasts or something? -- View this message in context: http://r.789695.n4.nabble.com/1-continuous-non-normal-variable-4-factors-1-continuous-covar

Re: [R] 1 continuous non-normal variable ~ 4 factors + 1 continuous covariate (with interactions)

Zitat von Alal : Thanks Im not sure about the gamma, but a survival analysis seems appropriate, but does it work for factors and continuous covariates? Do you have to verify some conditions beforehand? Here is an example: # test data... library(survival) set.seed(1007) x <- runif(50) mu <-

Re: [R] 1 continuous non-normal variable ~ 4 factors + 1 continuous covariate (with interactions)

Thanks Im not sure about the gamma, but a survival analysis seems appropriate, but does it work for factors and continuous covariates? Do you have to verify some conditions beforehand? -- View this message in context: http://r.789695.n4.nabble.com/1-continuous-non-normal-variable-4-factors-1-co

Re: [R] 1 continuous non-normal variable ~ 4 factors + 1 continuous covariate (with interactions)

Im struggling on something... I have one continuous variable (A), and I need to explain it with 4 factors, and maybe one continuous covariate. And of course, my variable A is not normal at all (it's a duration in seconds, whole numbers). What can I do? I would know how do deal with it if I had

[R] 1 continuous non-normal variable ~ 4 factors + 1 continuous covariate (with interactions)

Hello Im struggling on something... I have one continuous variable (A), and I need to explain it with 4 factors, and maybe one continuous covariate. And of course, my variable A is not normal at all (it's a duration in seconds, whole numbers). What can I do? I would know how do deal with it if

[R] 1

sd [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained

Re: [R] 1 - Survival Plot

Thanks for the responses guys! It worked like a charm! =) -- View this message in context: http://n4.nabble.com/1-Survival-Plot-tp1691512p1692516.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https:

Re: [R] 1 - Survival Plot

if you do: fit<-survfit (Surv(DTDMRS3, DMRS3) ~ RS2540477) fit$surv will have the survival function, and fit$time will have the failure times, these should give you what you want Hope this helps Corey - Corey Sparks, PhD Assistant Professor Department of Demography and Organization Studies

Re: [R] 1 - Survival Plot

Euphoria wrote: Hi all! I have created survival vs. time plots. Now I would like to plot (1 - Survival) vs. time. Is there a way for me to retrieve the survival estimate information, to which I can manually make an adjustment (ie; failure = 1 - survival) before I re-plot this information? Here

[R] 1 - Survival Plot

Hi all! I have created survival vs. time plots. Now I would like to plot (1 - Survival) vs. time. Is there a way for me to retrieve the survival estimate information, to which I can manually make an adjustment (ie; failure = 1 - survival) before I re-plot this information? Here is the code I use

Re: [R] "1 observation deleted due to missingness" from summary() on the result of aov()

On Feb 8, 2010, at 10:28 PM, bluesky...@gmail.com wrote: I have the R code at the end. The last command gives me "1 observation deleted due to missingness". I don't understand what this error message. Could somebody help me understand it and how to fix the problem? summary(afit)

[R] "1 observation deleted due to missingness" from summary() on the result of aov()

I have the R code at the end. The last command gives me "1 observation deleted due to missingness". I don't understand what this error message. Could somebody help me understand it and how to fix the problem? > summary(afit) Df Sum Sq Mean Sq F value Pr(>F) A 2 0.328 0

[R] 1 dimensional optimization with local minima

gt; Message: 114 > Date: Mon, 2 Nov 2009 23:00:40 -0800 (PST) > From: Jeroen Ooms > Subject: [R] 1 dimensional optimization with local minima > To: r-help@r-project.org > Message-ID: <26160001.p...@talk.nabble.com> > Content-Type: text/plain; charset=us-ascii > >

Re: [R] 1 dimensional optimization with local minima

_ Ravi Varadhan, Ph.D. Assistant Professor, Division of Geriatric Medicine and Gerontology School of Medicine Johns Hopkins University Ph. (410) 502-2619 email: rvarad...@jhmi.edu - Original Message - From: Jeroen Ooms Date: Tuesday, November 3, 2009

[R] 1 dimensional optimization with local minima

I am using numerical optimization to fit a 1 parameter model, in which the input parameter is bounded. I am currently using optimize(), however, the problem turns out to have local minima, and optimize does not always seem to find the global minimum. I could to write a wrapping function that tries

Re: [R] 1-Pearson's R Distance

t.org Assunto: Re: [R] 1-Pearson's R Distance Hi Rodrigo, afaik, (1 - r_Pearson)/2 is used rather than 1 - r_Pearson. This gives a distance measure ranging between 0 and 1 rather than 0 and 2. But after all, dies does not change anything substantial. see e.g. Theodoridis & Koutro

Re: [R] 1-Pearson's R Distance

At 5:00 PM +0100 11/27/08, Claudia Beleites wrote: Hi Rodrigo, afaik, (1 - r_Pearson)/2 is used rather than 1 - r_Pearson. This gives a distance measure ranging between 0 and 1 rather than 0 and 2. But after all, dies does not change anything substantial. see e.g. Theodoridis & Koutroumbas: Patt

Re: [R] 1-Pearson's R Distance

Rodrigo Aluizio wrote: Hi again List, Well this time I?m writing for a friend (really J). He needs to create a distance matrix based on an abundance matrix using the 1-Pearson?s R index. Well I told him to look at the proxy package, but there is only Pearson Index. He needs it to perform a clust

Re: [R] 1-Pearson's R Distance

Hi Rodrigo, afaik, (1 - r_Pearson)/2 is used rather than 1 - r_Pearson. This gives a distance measure ranging between 0 and 1 rather than 0 and 2. But after all, dies does not change anything substantial. see e.g. Theodoridis & Koutroumbas: Pattern Recognition. I didn't know of the proxy pack

[R] 1-Pearson's R Distance

Hi again List, Well this time I’m writing for a friend (really J). He needs to create a distance matrix based on an abundance matrix using the 1-Pearson’s R index. Well I told him to look at the proxy package, but there is only Pearson Index. He needs it to perform a clustering. Well, as soon as h

Re: [R] 1-SE rule in mvpart

R-users E-mail: r-help@r-project.org Hi! >I interprete this as following: the simplest tree with xerror under >min(xerror) + its own xstd >Neverthless, in some article I read the following rule: >the simplest tree with xerror under min(xerror) + xstd corresponding to the >min(xerror) >Is this a m

[R] 1-SE rule in mvpart

Hello, I'm using mvpart option xv="1se" to compute a regression tree of good size with the 1-SE rule. To better understand 1-SE rule, I took a look on its coding in mvpart, which is : Let z be a rpart object , xerror <- z$cptable[, 4] xstd <- z$cptable[, 5] splt <- min(seq(along = xerror)[xerror

Re: [R] (1-alpha)th percentile

hanen yahoo.fr> writes: > > > hello; > firstly, my gratitude to all who help me to find a function that allows me > to add confidence interval to my graph. > in order to calculate the (1-alpha)th percentile of for exemple an > F(df1,df2) distribution i do like this: > v<-df(alpha,df1,df2) > p

[R] (1-alpha)th percentile

hello; firstly, my gratitude to all who help me to find a function that allows me to add confidence interval to my graph. in order to calculate the (1-alpha)th percentile of for exemple an F(df1,df2) distribution i do like this: v<-df(alpha,df1,df2) percentile<-qf(v,df1,df2,alpha) if it is true

Re: [R] 1-pnorm values in a table

hsl.gov.uk> writes: [snip] > Try: > nrows <- 5 > mm <- matrix(rnorm(30),nrow=nrows) > sd.by.col <- apply(mm,2,sd) > mean.by.col <- apply(mm,2,mean) > values <- 1-mapply(pnorm, q=as.vector(mm), mean=rep(mean.by.col, > nrows)), sd=rep(sd.by.col, nrows))) values <- matrix(value

Re: [R] 1-pnorm values in a table

hsl.gov.uk> writes: [snip] > Try: > nrows <- 5 > mm <- matrix(rnorm(30),nrow=nrows) > sd.by.col <- apply(mm,2,sd) > mean.by.col <- apply(mm,2,mean) > values <- 1-mapply(pnorm, q=as.vector(mm), mean=rep(mean.by.col, nrows)), > sd=rep(sd.by.col, nrows))) > values <- matrix(values, nrow=5) > >

Re: [R] 1-pnorm values in a table

This is a bit ugly but I think it works. myf <- function(x) 1-pnorm(x,mean(x), sd(x)) results <- apply(test, 2, myf) mymeans <- apply(test, 2, mean); mymeans for (i in 1:length(test)){ test[,i][test[,1]>=mymeans[i]] <- NA } results[is.na(tes

Re: [R] 1-pnorm values in a table

> I've read in a csv file (test.csv) which gives me the following table: > >Hin1 Hin2 Hin3Hin4 Hin5 Hin6 > HAI1 9534.83 4001.74 157.16 3736.93 484.60 59.25 > HAI2 13272.48 1519.88 36.35 33.64 46.68 82.11 > HAI3 12587.71 5686.94 656.62 572.29 351.60 136.91 > H

[R] 1-pnorm values in a table

Hi, I've read in a csv file (test.csv) which gives me the following table: Hin1 Hin2 Hin3Hin4 Hin5 Hin6 HAI1 9534.83 4001.74 157.16 3736.93 484.60 59.25 HAI2 13272.48 1519.88 36.35 33.64 46.68 82.11 HAI3 12587.71 5686.94 656.62 572.29 351.60 136.91 HAI4

Re: [R] 1-d function fitting

Rolf Turner wrote: > On 26/10/2007, at 10:14 AM, m p wrote: > > >> Hello, >> I'd like to check if my data can be well approximated with a function >> (1+x/L) exp(-x/L) >> and calculate the best value for L. Is there some package in R that >> would simplify that task? >> Thanks, >> Mark >>

Re: [R] 1-d function fitting

No, that's not my homework. Does that seem so easy? Mark Rolf Turner <[EMAIL PROTECTED]> wrote: On 26/10/2007, at 10:14 AM, m p wrote: > Hello, > I'd like to check if my data can be well approximated with a function > (1+x/L) exp(-x/L) > and calculate the best value for L. Is there some package

Re: [R] 1-d function fitting

On 26/10/2007, at 10:14 AM, m p wrote: > Hello, > I'd like to check if my data can be well approximated with a function > (1+x/L) exp(-x/L) > and calculate the best value for L. Is there some package in R that > would simplify that task? > Thanks, > Mark Is this a homework question?

[R] 1-d function fitting

Hello, I'd like to check if my data can be well approximated with a function (1+x/L) exp(-x/L) and calculate the best value for L. Is there some package in R that would simplify that task? Thanks, Mark __ [[alternative HTML version de